Recommended PYQs (STRICTLY NCERT Based) Alternating Current Physics NEET Practice Questions, MCQs, Past Year Questions (PYQs), NCERT Questions, Question Bank, Class 11 and Class 12 Questions, and PDF solved with answers

In an ideal transformer, the turns ratio is \(\cfrac{N_p}{N_s}=\cfrac{1}{2} .\) The ratio \(V_s:V_p\) is equal to (the symbols carry their usual meaning):

1.	\(2:1\)	2.	\(1:1\)
3.	\(1:4\)	4.	\(1:2\)

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A \(10~\mu\text F\) capacitor is connected to a \(210~\text V,50~\text{Hz}\) source as shown in the figure. The peak current in the circuit is nearly \((\pi = 3.14)\):

1. \(0.93~\text A\)
2. \(1.20~\text A\)
3. \(0.35~\text A\)
4. \(0.58~\text A\)

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\(L,C\) and \(R\) represent the value of inductance, capacitance and resistance, respectively. The factor which has the same dimensions as that of the inverse of resonance frequency is:
1. \(\sqrt{LC}\)
2. \(\sqrt{\dfrac{L}{C}}\)
3. \(\dfrac{C}{L}\)
4. \(\dfrac{R}{L}\)

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In the circuit shown below, the inductance \(L\) is connected to a source. The current flowing in the circuit is \({I=I_{0}\sin\omega t.}\) The voltage drop \((V_L)\) across \(L\) is:

1. \(\omega L~I_0\sin\omega t\)
2. \(\frac{{I}_0}{\omega{L}}\sin\omega t\)
3. \(\frac{{I}_0}{\omega{L}}\cos\omega t\)
4. \(\omega L~I_0\cos\omega t\)

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A step-up transformer is connected to an AC mains supply of \(220~\text V\) to operate at \(11000~\text V, 88\) watt. The current in the secondary circuit, ignoring the power loss in the transformer, is:

1.	\(8~\text{mA}\)	2.	\(4~\text{mA}\)
3.	\(0.4~\text{A}\)	4.	\(4~\text{A}\)

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An ac source is connected to a capacitor \(C\). Due to decrease in its operating frequency:
1. capacitive reactance remains constant
2. capacitive reactance decreases.
3. displacement current increases.
4. displacement current decreases.

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A \(12~\text{V},60~\text{W}\) lamp is connected to the secondary of a step down transformer, whose primary is connected to ac mains of \(220~\text{V}\). Assuming the transformer to be ideal, what is the current in the primary winding?
1. \(0.37~\text{A}\)
2. \(0.27~\text{A}\)
3. \(2.7~\text{A}\)
4. \(3.7~\text{A}\)

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In a series \({LCR}\) circuit, the inductance \({L}\) is \(10~\text{mH}\), capacitance \({C}\) is \(1~\mu\text{F}\) and resistance \({R}\) is \(100~\Omega\). The frequency at which resonance occurs is:

1.	\(1.59~\text{kHz}\)	2.	\(15.9~\text{rad/s}\)
3.	\(15.9~\text{kHz}\)	4.	\(1.59~\text{rad/s}\)

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The net impedance of circuit (as shown in the figure) will be:

1. \(25~\Omega\)
2. \(10\sqrt{2}~\Omega\)
3. \(15~\Omega\)
4. \(5\sqrt{5}~\Omega\)

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An AC source is connected to the given circuit. The value of \(\phi\) will be:

1.	\(60^\circ\)	2.	\(90^\circ\)
3.	\(30^\circ\)	4.	\(45^\circ\)

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