Match the items given in Column I with the type of solutions given in Column II.
Column I | Column II |
A. Soda water | 1. A solution of gas in solid |
B. Sugar solution | 2. A solution of gas in liquid |
C. German silver | 3. A solution of solid in liquid |
D. Hydrogen gas in palladium | 4. A solution of solid in solid |
Codes:
A | B | C | D | |
1. | 2 | 1 | 4 | 3 |
2. | 1 | 2 | 3 | 4 |
3. | 2 | 3 | 4 | 1 |
4. | 4 | 1 | 3 | 2 |
Select the correct option based on statements below:
Assertion (A): | Molarity of a solution in liquid state changes with temperature. |
Reason (R): | The volume of a solution changes with change in temperature. |
1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
3. | (A) is True but (R) is False. |
4. | (A) is False but (R) is True. |
Match the terms given in Column I with expressions given in Column II.
Column I (Term) | Column II (Expression) |
A. Mass percentage | 1. \(\text{Number of moles of the solute component} \over \text{Volume of solution in litres}\) |
B. Volume percentage | 2. \(\text{Number of moles of the solute component} \over \text{Mass of solvent in kilograms}\) |
C. Molarity | 3. \({\text{Volume of the solute component in solution} \over \text{Total volume of solution}} \times 100\) |
D. Molality | 4. \({\text{Mass of the solute component in solution} \over \text{Total Mass of solution}} \times 100\) |
Codes:
A | B | C | D | |
1. | 2 | 3 | 4 | 1 |
2. | 1 | 2 | 3 | 4 |
3. | 1 | 4 | 3 | 2 |
4. | 4 | 3 | 1 | 2 |
An antifreeze solution is prepared from 222.6 g of ethylene glycol (C2H6O2) and 200 g of water. The molality of the solution would be:
1. | 6.9 m | 2. | 17.9 m |
3. | 29.9 m | 4. | 21.9 m |
The temperature dependent term among the following is -
1. | Molality | 2. | Molarity |
3. | Mole fraction | 4. | Weight percentage |
1. | \(\text X_{\text{mole fraction}}=\frac{\text n_{\text{solute}}}{\text n_{\text{solution}}}\) |
2. | \(\text{Molarity}=\frac{\text{amount of solute (g)}}{\text{volume of solution (mL)}}\) |
3. | \(\text{Molality}=\frac{\text{Number of mole of solute}}{\text{amount of solvent (kg)}}\) |
4. | \(\text{Mass percentage}=\frac{\text{mass of the component in the solution}}{\text{Total mass of the solution}}\times100 \) |
The mass percentage of aspirin (C9H8O4) in acetonitrile (CH3CN) when 6.5 g of C9H8O4 is dissolved in 450 g of CH3CN will be:
1. 1.424%
2. 4.424%
3. 5.124%
4. 2.124%
The molarity of H2SO4 solution that has a density 1.84 g/cc at 35 oC and contains 98 % H2SO4 by weight is-
1. | 1.84 M | 2. | 81.4 M |
3. | 18.4 M | 4. | 184 M |
To make 2.5 kg of 0.25 m aqueous solution, the mass of urea required is-
1. | 73 g | 2. | 37 g |
3. | 48 g | 4. | 24 g |
To minimize the painful effects accompanying deep sea diving, oxygen diluted with less soluble helium gas is used as breathing gas by the divers. This is an example of the application of:
1. | Raoult's law | 2. | Henry's law |
3. | Ideal gas Equation | 4. | All of the above |