Q. No.The standard electrode potential for Sn4+/Sn2+ couple is +0.15 V and that for the Cr3+/Cr couple is -0.74 V. These two couples in their standard state are connected to make a cell. The cell potential will be:
| 1. | +0.89 V | 2. | +0.18 V |
| 3. | +1.83 V | 4. | +1.199 V |
Zn(s) + Ag2O(s) + H2O(l) \(\rightleftharpoons\) 2Ag(s) + Zn2+(aq) + 2OH–(aq)
If half-cell potentials are-
| Zn2+(aq) + 2e–→ Zn(s) | Eo = – 0.76 V |
| Ag2O(s) + H2O(l) + 2e– → 2Ag(s) + 2OH–(aq) | Eo = 0.34 V |
The cell potential will be:
| 1. | 0.42 V | 2. | 0.84 V |
| 3. | 1.34 V | 4. | 1.10 V |
Given the standard electrode potentials:
| K+/K = –2.93 V |
| Ag+/Ag = 0.80 V |
| Hg2+/Hg = 0.79 V |
| Mg2+/Mg = –2.37 V |
| Cr3+/Cr = – 0.74 V |
| 1. | Cr < Mg < K < Ag < Hg | 2. | Mg < K < Ag < Hg < Cr |
| 3. | K < Ag < Hg < Cr < Mg | 4. | Ag < Hg < Cr < Mg < K |
Molten sodium chloride conducts electricity due to the presence of:
1. Free ions.
2. Free molecules.
3. Free electrons.
4. Atoms of sodium and chlorine.
The metal that cannot be produced upon reduction of its oxide by aluminium is :
| 1. | K | 2. | Mn |
| 3. | Cr | 4. | Fe |
The difference between the electrode potentials of two electrodes when no current is drawn through the cell is called:
1. Cell potential.
2. Cell emf.
3. Potential difference.
4. Cell voltage.
A gas X at 1 atm is bubbled through a solution containing a mixture of 1 M Y- and 1 M Z- at 25 oC . If the reduction potential of Z > Y > X, then:
| 1. | Y will oxidize X but not Z. | 2. | Y will oxidize Z but not X. |
| 3. | Y will oxidize both X and Z. | 4. | Y will reduce both X and Z. |
If = -0.441 V and = 0.771 V, the standard emf of the reaction:
Fe + 2Fe3+→ 3Fe2+ will be:
| 1. | 0.330 V | 2. | 1.653 V |
| 3. | 1.212 V | 4. | 0.111 V |
Consider the following relations for emf of an electrochemical cell:
| (a) | emf of cell = (Oxidation potential of anode) – (Reduction potential of cathode) |
| (b) | emf of cell = (Oxidation potential of anode) + (Reduction potential of cathode) |
| (c) | emf of cell = (Reduction potential of anode) + (Reduction potential of cathode) |
| (d) | emf of cell = (Oxidation potential of anode) – (Oxidation potential of cathode) |
The correct relation among the given options is:
| 1. | (a) and (b) | 2. | (c) and (d) |
| 3. | (b) and (d) | 4. | (c) and (a) |
The correct statement among the following options is:
| 1. | Ecell and ∆rG of cell reaction are both extensive properties. |
| 2. | Ecell and ∆rG of cell reaction are both intensive properties. |
| 3. | Ecell is an intensive property while ∆rG of cell reaction is an extensive property. |
| 4. | Ecell is an extensive property while ∆rG of cell reaction is an intensive property. |
© 2024 GoodEd Technologies Pvt. Ltd.