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Q. No.Two identical rectangular plane sheet \(A\) and \(B\) each of surface charge density \(\varepsilon_0~ \text{Cm}^{-2}\) are placed parallel to each other as shown in figure. The electric field at the mid point \(P\) will be:
1. \(2 ~\text{NC}^{-1}\)
2. \(1~\text{NC}^{-1}\)
3. \(0.5~\text{NC}^{-1}\)
4. zero
1. \(2 ~\text{NC}^{-1}\)
2. \(1~\text{NC}^{-1}\)
3. \(0.5~\text{NC}^{-1}\)
4. zero
Subtopic: Electric Field |
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From NCERT
NEET - 2024
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Match List-I with List-II:
(Here symbols have their usual meaning and \(R\) is the radius of the thin shell)
Choose the correct answer from the options given below:
| List-I (Application of Gauss Law) |
List-II (Value of \(|E|\)) |
||
| A. | The field inside a thin shell | I. | \( \dfrac{\lambda}{2 \pi \varepsilon_0 r} \hat{n} \) |
| B. | The field outside a thin shell | II. | \( \dfrac{q}{4 \pi \varepsilon_0 R^2} \hat{r} \) |
| C. | The field of thin shell at the surface | III. | \( \dfrac{q}{4 \pi \varepsilon_0 r^2} \hat{r}\) |
| D. | The field due to a long charged wire | IV. | zero |
Choose the correct answer from the options given below:
| 1. | A-IV, B-III, C-I, D-II |
| 2. | A-I, B-II, C-III, D-IV |
| 3. | A-IV, B-III, C-II, D-I |
| 4. | A-I, B-III, C-II, D-IV |
Subtopic: Gauss's Law |
85%
From NCERT
NEET - 2024
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A particle of mass \(m\) and charge \(q\) is placed in a uniform electric field \(E\) at \(t=0~\text s.\) The kinetic energy of the particle after time \(t\) is:
1. \(\dfrac{Eqm}{t}\)
2. \(\dfrac{E^2q^2t^2}{2m}\)
3. \(\dfrac{2E^2t^2}{qm}\)
4. \(\dfrac{Eq^2m}{2t^2}\)
1. \(\dfrac{Eqm}{t}\)
2. \(\dfrac{E^2q^2t^2}{2m}\)
3. \(\dfrac{2E^2t^2}{qm}\)
4. \(\dfrac{Eq^2m}{2t^2}\)
Subtopic: Electric Field |
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From NCERT
NEET - 2024
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A metal cube of a side \(5~\text{cm},\) is charged with \(6~\text{μC.}\) The surface charge density on the cube, is:
| 1. | \(0.125\times10^{-3}~\text{C m}^{-2}\) | 2. | \(0.25\times10^{-3}~\text{C m}^{-2}\) |
| 3. | \(4\times10^{-3}~\text{C m}^{-2}\) | 4. | \(0.4\times10^{-3}~\text{C m}^{-2}\) |
Subtopic: Electric Charge |
From NCERT
NEET - 2024
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If \(\oint_s \vec{E} \cdot {d \vec S}=0\) over a surface, then:
| 1. | the electric field inside the surface is necessarily uniform. |
| 2. | the number of flux lines entering the surface must be equal to the number of flux lines leaving it. |
| 3. | the magnitude of electric field on the surface is constant. |
| 4. | all the charges must necessarily be inside the surface. |
Subtopic: Gauss's Law |
79%
From NCERT
NEET - 2023
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An electric dipole is placed at an angle of \(30^\circ\) with an electric field of intensity \(2\times 10^5 ~\text{NC}^{-1}\). It experiences a torque equal to \(4~\text{N-m}\). If the dipole length is \(2\) cm, calculate the magnitude of the charge on the dipole.
1. \(2~\text{mC}\)
2. \(8~\text{mC}\)
3. \(6~\text{mC}\)
4. \(4~\text{mC}\)
1. \(2~\text{mC}\)
2. \(8~\text{mC}\)
3. \(6~\text{mC}\)
4. \(4~\text{mC}\)
Subtopic: Electric Dipole |
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From NCERT
NEET - 2023
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According to Gauss law of electrostatics, electric flux through a closed surface depends on:
| 1. | the area of the surface. |
| 2. | the quantity of charges enclosed by the surface. |
| 3. | the shape of the surface. |
| 4. | the volume enclosed by the surface. |
Subtopic: Gauss's Law |
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From NCERT
NEET - 2023
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A charge \(Q~\mu\text{C}\) is placed at the centre of a cube. The flux coming out from any one of its faces will be (in SI units):
| 1. | \(\dfrac{Q}{\varepsilon_0}\times10^{-6}\) | 2. | \(\dfrac{2Q}{3\varepsilon_0}\times10^{-3}\) |
| 3. | \(\dfrac{Q}{6\varepsilon_0}\times10^{-3}\) | 4. | \(\dfrac{Q}{6\varepsilon_0}\times10^{-6} \) |
Subtopic: Gauss's Law |
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From NCERT
NEET - 2023
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Two point charges \({-q}\) and \({+q}\) are placed at a distance of \({L},\) as shown in the figure.
The magnitude of electric field intensity at a distance \({R}~(R \gg L )\) varies as:
The magnitude of electric field intensity at a distance \({R}~(R \gg L )\) varies as:
| 1. | \(\dfrac{1}{{R}^{6}}\) | 2. | \(\dfrac{1}{{R}^{2}}\) |
| 3. | \(\dfrac{1}{{R}^{3}}\) | 4. | \(\dfrac{1}{{R}^{4}}\) |
Subtopic: Electric Dipole |
71%
From NCERT
NEET - 2022
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Twelve point charges each of charge \(q~\text C\) are placed at the circumference of a circle of radius \(r~\text m\) with equal angular spacing. If one of the charges is removed, the net electric field (in \(\text{N/C}\)) at the centre of the circle is:
(\(\varepsilon_0 \)-permittivity of free space)
| 1. | \(\frac{13q}{4\pi \varepsilon_0r^2}\) | 2. | zero |
| 3. | \(\frac{q}{4\pi \varepsilon_0r^2}\) | 4. | \(\frac{12q}{4\pi \varepsilon_0r^2}\) |
Subtopic: Electric Field |
64%
From NCERT
NEET - 2022
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