Consider the following nuclear reaction:
\({}^{238}_{}\mathrm{U} \rightarrow {}^{234}_{}\mathrm{Th} + {}^{4}_{}\mathrm{He}\)
Take masses of \({}^{238}\mathrm{U},{}^{238}\mathrm{Th}\) and \({}^{4}\mathrm{He}\) as \(238.050~\text{u},\) \(234.043~\text{u}\) and \(4.003~\text{u},\) respectively. The \(Q\) value for the reaction, in keV, is:
(given: \(1~\text{u}=931.5\) MeV c-2)
1. \(3740\)
2. \(3726\)
3. \(3730\)
4. \(3736\)
Subtopic:  Nuclear Binding Energy |
 52%
Level 3: 35%-60%
NEET - 2026
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Water is used as a coolant in a nuclear reactor because of its:
1. high thermal expansion coefficient
2. high specific heat capacity
3. low density
4. low boiling point
Subtopic:  Nuclear Binding Energy |
 69%
Level 2: 60%+
NEET - 2024
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A nucleus with mass number \(240\) breaks into fragments each of mass number \(120.\) The binding energy per nucleon of unfragmented nuclei is \(7.6~\text{MeV}\) while that of fragments is \(8.5~\text{MeV}.\) The total gain in the binding energy in the process is:

1. \(804~\text{MeV}\) 2. \(216~\text{MeV}\)
3. \(0.9~\text{MeV}\) 4. \(9.4~\text{MeV}\)
Subtopic:  Nuclear Binding Energy |
 66%
Level 2: 60%+
NEET - 2021
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