A hydrogen atom is excited from the ground state to the state of principal quantum number 4. Then the number of spectral lines observed will be:
1. 3
2. 6
3. 5
4. 2
The ratio of the longest wavelengths corresponding to the Lyman and Balmer series in the hydrogen spectrum is:
1. | \(\frac{3}{23}\) | 2. | \(\frac{7}{29}\) |
3. | \(\frac{9}{31}\) | 4. | \(\frac{5}{27}\) |
Given that the value of the Rydberg constant is \(10^{7}~\text{m}^{-1}\), what will be the wave number of the last line of the Balmer series in the hydrogen spectrum?
1. \(0.5 \times 10^{7}~\text{m}^{-1}\)
2. \(0.25 \times 10^{7} ~\text{m}^{-1}\)
3. \(2.5 \times 10^{7}~\text{m}^{-1}\)
4. \(0.025 \times 10^{4} ~\text{m}^{-1}\)
When an electron transitions from n = 4 to n = 2, then the emitted line in the spectrum will be:
1. | the first line of the Lyman series. |
2. | the second line of the Balmer series. |
3. | the first line of the Paschen series. |
4. | the second line of the Paschen series. |
What is the ratio of the largest to shortest wavelengths in the Lyman series of hydrogen spectra?
1.
2.
3.
4.
What is the ratio of wavelengths of the last line of the Balmer series and the last line of the Lyman series?
1. 1
2. 4
3. 0.5
4. 2
What is the ratio of the longest to shortest wavelengths in Brackett series of hydrogen spectra?
1.
2.
3.
4.
In an atom, if the transition from n = 4 to n = 3 gives ultraviolet radiation, then to obtain infrared radiation, the transition should be:
1. | 5 → 4 | 2. | 3 → 2 |
3. | 2 → 1 | 4. | 3 → 1 |
E1, E2 and E3 are energies of an electron in three consecutive energy levels of a hydrogen-like atom, such that E1<E2<E3. The wavelength emitted in the transition from E3 to E2 is λ2 and the wavelength emitted in the transition from E2 to E1 is λ1. The wavelength emitted in transition from E3 to E1 is:
1.
2.
3.
4.
If the wavelength of the first line in the Balmer Series of the hydrogen spectrum is λ, then what is the wavelength of the second line in this series?
1.
2.
3.
4.