The energy equivalent of one atomic mass unit is:
1.
2.
3. 931 MeV
4. 9.31 MeV
A nuclear reaction along with the masses of the particle taking part in it is as follows;
The energy Q liberated in the reaction is:
1. 1.234 MeV
2. 0.931 MeV
3. 0.465 MeV
4. 1.862 MeV
Determine the energy released in the process:
Given: M = 2.01471 amu
M= 4.00388 amu
1. 3.79 MeV
2.13.79 MeV
3. 0.79 MeV
4. 23.79 MeV
The energy required in \(\mathrm{MeV} / \mathrm{c}^2\) to separate \({ }_8^{16} \mathrm{O}\) into its constituents is:
(Given mass defect for \({ }_8^{16} \mathrm{O}=0.13691 \mathrm{u}\))
1. \(127.5\)
2. \(120.0\)
3. \(222.0\)
4. \(119.0\)
If an electron and a positron annihilate, then the energy released is:
1.
2.
3.
4.
The energy equivalent of \(0.5\) g of a substance is:
1. \(4.5\times10^{13}\) J
2. \(1.5\times10^{13}\) J
3. \(0.5\times10^{13}\) J
4. \(4.5\times10^{16}\) J
If a proton and anti-proton come close to each other and annihilate, how much energy will be released?
1. | \(1.5 \times10^{-10}~\text{J}\) | 2. | \(3 \times10^{-10}~\text{J}\) |
3. | \(4.5 \times10^{-10}~\text{J}\) | 4. | None of these |
=Calculate the Q-value of the nuclear reaction:
\(2~{ }_{6}^{12} \mathrm{C}\rightarrow{ }_{10}^{20} \mathrm{Ne}+{ }_2^4 \mathrm{He}\)
The following data are given:
\(m({ }_{6}^{12} \mathrm{C})=12.000000~\text{u}\)
\(m({ }_{10}^{20} \mathrm{Ne})=19.992439~\text{u}\)
\(m({ }_{2}^{4} \mathrm{He})=4.002603~\text{u}\)
1. \(3.16~\text{MeV}\)
2. \(5.25~\text{MeV}\)
3. \(3.91~\text{MeV}\)
4. \(4.65~\text{MeV}\)
A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in the fusion reaction is 0.02866 u. The energy liberated per nucleon is: (Given 1 u = 931 MeV)
1. | 26.7 MeV | 2. | 6.675 MeV |
3. | 13.35 MeV | 4. | 2.67 MeV |
The rest energy of an electron is:
1. | 510 KeV | 2. | 931 KeV |
3. | 510 MeV | 4. | 931 MeV |