Two circuits have coefficient of mutual induction of \(0.09\) henry. Average emf induced in the secondary by a change of current from \(0\) to \(20\) ampere in \(0.006\) second in the primary will be:
1. \(120\) V
2. \(80\) V
3. \(200\) V
4. \(300\) V

A pair of adjacent coils has a mutual inductance of \(1.5\) H. If the current in one coil changes from \(0\) to \(20\) A in \(0.5\) s, what is the change of flux linkage with the other coil?
1. \(35\) Wb
2. \(25\) Wb
3. \(30\) Wb
4. \(20\) Wb

With the decrease of current in the primary coil from \(2\) A to zero in \(0.01\) s, the emf generated in the secondary coil is \(1000~\text{V}\). The mutual inductance of the two coils is:
1. \(1.25\) H
2. \(2.50\) H
3. \(5.00\) H
4. \(10.00\) H

The coefficient of mutual inductance between two coils depends upon:

Two coils of \(10\) turns each are arranged such that the mutual inductance between them is \(150\) mH. The magnetic flux linked through one coil when \(2\) amperes current will flow in another coil, will be:
1. \(1\times 10^{-3}~\text{Wb}\)
2. \(10\times 10^{-3}~\text{Wb}\)
3. \(20\times 10^{-3}~\text{Wb}\)
4. \(30\times 10^{-3}~\text{Wb}\)

Two coils have a mutual inductance of \(5\) mH. The current changes in the first coil according to the equation \(I=I_{0}\cos\omega t,\)where \(I_{0}=10~\text{A}\)and\(\omega = 100\pi ~\text{rad/s}\). The maximum value of emf induced in the second coil is:
1. \(5\pi\) Volt
2. \(2\pi\) Volt
3. \(4\pi\) Volt
4. \(\pi\) Volt

Two circular coils can be arranged in any of the three situations shown in the figure. Their mutual inductance will be:

A straight solenoid has \(50\) turns per cm in primary coil and \(200\) turns in the secondary coil. The area of cross-section of the solenoid is \(4\) cm². Calculate the mutual inductance.
1. \(5.0~\text{H}\)
2. \(5.0\times 10^{-4}~\text{H}\)
3. \(2.5~\text{H}\)
4. \(2.5\times 10^{-4}~\text{H}\)