A mass of 30 g is attached with two springs having spring constant 100 N/m and 200 N/m and other ends of springs are attached to rigid walls as shown in the given figure. The angular frequency of oscillation will be
1.
2.
3. 100 rad/s
4. 200 rad/s
Two equations of S.H.M. are and . The phase difference between the two is:
1. \(0^\circ\)
2. \(\alpha^\circ\)
3. \(90^\circ\)
4. \(180^\circ\)
If a particle in SHM has a time period of \(0.1\) s and an amplitude of \(6\) cm, then its maximum velocity will be:
1. \(120 \pi\) cm/s
2. \(0.6 \pi\) cm/s
3. \(\pi\) cm/s
4. \(6\) cm/s
If the potential energy U (in J) of a body executing SHM is given by U = 20 + 10 (100t), then the minimum potential energy of the body will be:
1. | Zero | 2. | 30 J |
3. | 20 J | 4. | 40 J |
The kinetic energy (K) of a simple harmonic oscillator varies with displacement (x) as shown. The period of the oscillation will be: (mass of oscillator is 1 kg)
1. | sec | 2. | sec |
3. | sec | 4. | 1 sec |
The equation of an SHM is given as y=3sinωt + 4cosωt where y is in centimeters. The amplitude of the SHM will be?
1. | 3 cm | 2. | 3.5 cm |
3. | 4 cm | 4. | 5 cm |
The time periods for the figures (a) and (b) are respectively. If all surfaces shown below are smooth, then the ratio will be:
1. 1:
2. 1: 1
3. 2: 1
4. : 2
A particle is attached to a vertical spring and pulled down a distance of 0.01 m below its mean position and released. If its initial acceleration is 0.16 , then its time period in seconds will be:
1.
2.
3.
4.
A particle is executing linear simple harmonic motion with an amplitude \(a\) and an angular frequency \(\omega\). Its average speed for its motion from extreme to mean position will be:
1. \(\frac{a\omega}{4}\)
2. \(\frac{a\omega}{2\pi}\)
3. \(\frac{2a\omega}{\pi}\)
4. \(\frac{a\omega}{\sqrt{3}\pi}\)
Two simple harmonic motions, and are superimposed on a particle of mass m. The maximum kinetic energy of the particle will be:
1.
2.
3.
4. Zero