Statement I: | In an AC circuit, the current through a capacitor leads the voltage across it. |
Statement II: | \(\pi.\) | In AC circuits containing pure capacitance only, the phase difference between the current and the voltage is
1. | Both Statement I and Statement II are correct. |
2. | Both Statement I and Statement II are incorrect. |
3. | Statement I is correct but Statement II is incorrect. |
4. | Statement I is incorrect but Statement II is correct. |
1. | \(20~\mathrm{V}\) and \(2.0~\mathrm{mA}\) |
2. | \(10~\mathrm{V}\) and \(0.5~\mathrm{mA}\) |
3. | zero and therefore no current |
4. | \(20~\mathrm{V}\) and \(0.5~\mathrm{mA}\) |
1. | \(\frac{\omega L}{R}\) | depends on the ratio
2. | \(\sqrt{(\omega L)^2+R^2}\) | depends on the quantity
3. | \(L\) and \(R,\) but not on \(\omega\) | depends on
4. | is independent of \(L,R,\omega\) |
1. | \(100~\Omega.\) | the impedance in the circuit is
2. | \(200~\Omega.\) | the resistance in the circuit is
3. | \(484\) W. | the power dissipated is
4. | all the above are true. |
An AC source given by \(V=V_m\sin\omega t\) is connected to a pure inductor \(L\) in a circuit and \(I_m\) is the peak value of the AC current. The instantaneous power supplied to the inductor is:
1. \(\frac{V_mI_m}{2}\mathrm{sin}(2\omega t)\)
2. \(-\frac{V_mI_m}{2}\mathrm{sin}(2\omega t)\)
3. \({V_mI_m}\mathrm{sin}^{2}(\omega t)\)
4. \(-{V_mI_m}\mathrm{sin}^{2}(\omega t)\)
1. | \(\nu=100 \mathrm{~Hz} ; ~\nu_0=\frac{100}{\pi} \mathrm{~Hz}\) |
2. | \(\nu_0=\nu=50 \mathrm{~Hz}\) |
3. | \(\nu_0=\nu=\frac{50}{\pi} \mathrm{Hz}\) |
4. | \(\nu_{0}=\frac{50}{\pi}~ \mathrm{Hz}, \nu=50 \mathrm{~Hz}\) |
1. | \(1 / \sqrt{2}\) times the rms value of the AC source |
2. | the value of voltage supplied to the circuit |
3. | the rms value of the AC source |
4. | \(\sqrt{2}\) times the rms value of the AC source |