The sum of the numbers \(436.32,227.2,\) and \(0.301\) in the appropriate significant figures is:
1. | \( 663.821 \) | 2. | \( 664 \) |
3. | \( 663.8 \) | 4. | \(663.82\) |
The mass and volume of a body are \(4.237~\text{grams}\) and \(2.5~\text{cm}^3\), respectively. The density of the material of the body in correct significant figures will be:
1. \(1.6048~\text{grams cm}^{-3}\)
2. \(1.69~\text{grams cm}^{-3}\)
3. \(1.7~\text{grams cm}^{-3}\)
4. \(1.695~\text{grams cm}^{-3}\)
The numbers \(2.745\) and \(2.735\) on rounding off to \(3\) significant figures will give respectively,
1. \(2.75\) and \(2.74\)
2. \(2.74\) and \(2.73\)
3. \(2.75\) and \(2.73\)
4. \(2.74\) and \(2.74\)
The length and breadth of a rectangular sheet are \(16.2\) cm and \(10.1\) cm, respectively. The area of the sheet in appropriate significant figures and error would be, respectively,
1. | \(164\pm3~\text{cm}^2\) | 2. | \(163.62\pm2.6~\text{cm}^2\) |
3. | \(163.6\pm2.6~\text{cm}^2\) | 4. | \(163.62\pm3~\text{cm}^2\) |
Which of the following pairs of physical quantities does not have the same dimensional formula?
1. | work and torque |
2. | angular momentum and Planck's constant |
3. | tension and surface tension |
4. | impulse and linear momentum |
The measure of two quantities along with the precision of respective measuring instrument is . The value of AB will be:
1. (0.25 0.08) m
2. (0.25 0.5) m
3. (0.25 0.05) m
4. (0.25 0.135) m
You measure two quantities as A = 1.0 m 0.2 m, B = 2.0 m 0.2 m. We should report the correct value for as
1. 1.4 m 0.4 m
2. 1.41 m 0.15 m
3. 1.4 m 0.3 m
4. 1.4 m 0.2 m
Which of the following measurement is most precise?
1. \(5.00\) mm
2. \(5.00\) cm
3. \(5.00\) m
4. \(5.00\) km
The mean length of an object is \(5~\text{cm}\). Which of the following measurements is the most accurate?
1. | \(4.9~\text{cm}\) | 2. | \(4.805~\text{cm}\) |
3. | \(5.25~\text{cm}\) | 4. | \(5.4~\text{cm}\) |
Young's modulus of steel is \(1.9 \times 10^{11} \mathrm{~N} / \mathrm{m}^2\). When expressed in CGS units of \(\mathrm{dyne/cm^2}\), it will be equal to: \((1 \mathrm{~N}=10^5 \text { dyne, } 1 \mathrm{~m}^2=10^4 \mathrm{~cm}^2)\)
1. \( 1.9 \times 10^{10} \)
2. \( 1.9 \times 10^{11} \)
3. \( 1.9 \times 10^{12} \)
4. \( 1.9 \times 10^9\)