Assertion (A): | The potential \((V)\) at any axial point, at \(2~\text m\) distance (\(r\)) from the centre of the dipole of dipole moment vector \(\vec P\) of magnitude, \(4\times10^{-6}~\text{C m},\) is \(\pm9\times10^3~\text{V}.\) (Take \({\frac{1}{4\pi\varepsilon_0}}=9\times10^9\) SI units) |
Reason (R): | \(V=\pm{\large\frac{2P}{4\pi\varepsilon_0r^2}},\) where \(r\) is the distance of any axial point situated at \(2~\text m\) from the centre of the dipole. |
1. | Both (A) and (R) are True and (R) is NOT the correct explanation of (A). |
2. | (A) is True but (R) is False. |
3. | (A) is False but (R) is True. |
4. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
1. | \(\frac{rV}{R^2}\) | 2. | \(\frac{R^2V}{r^3}\) |
3. | \(\frac{RV}{r^2}\) | 4. | \(\frac{V}{r}\) |
1. | dependent on the material property of the sphere |
2. | more on bigger sphere |
3. | more on smaller sphere |
4. | equal on both the spheres |
A hollow metal sphere of radius \(R\) is given \(+Q\) charges to its outer surface. The electric potential at a distance \(\frac{R}{3}\) from the centre of the sphere will be:
1. \(\frac{1}{4\pi \varepsilon_0}\frac{Q}{9R}\)
2. \(\frac{3}{4\pi \varepsilon_0}\frac{Q}{R}\)
3. \(\frac{1}{4\pi \varepsilon_0}\frac{Q}{3R}\)
4. \(\frac{1}{4\pi \varepsilon_0}\frac{Q}{R}\)
Two charged spherical conductors of radii \(R_1\) and \(R_2\) are connected by a wire. The ratio of surface charge densities of spheres \(\left ( \frac{\sigma _{1}}{\sigma _{2}}\right )\) is:
1. \(\sqrt{\frac{R_1}{R_2}}\)
2. \(\frac{R^2_1}{R^2_2}\)
3. \(\frac{R_1}{R_2}\)
4. \(\frac{R_2}{R_1}\)
Twenty seven drops of same size are charged at \(220~\text{V}\) each. They combine to form a bigger drop. Calculate the potential of the bigger drop.
1. \(1520~\text{V}\)
2. \(1980~\text{V}\)
3. \(660~\text{V}\)
4. \(1320~\text{V}\)
The variation of electrostatic potential with radial distance \(r\) from the centre of a positively charged metallic thin shell of radius \(R\) is given by the graph:
1. | 2. | ||
3. | 4. |