1. | \(9~{\mu \text{F}}\) | 2. | \(2~{\mu \text{F}}\) |
3. | \(3~{\mu \text{F}}\) | 4. | \(6~{\mu \text{F}}\) |
1. | \(30~\mu \text{F}\) | 2. | \(15~\mu \text{F}\) |
3. | \(25~\mu\text{F}\) | 4. | \(20~\mu\text{F}\) |
Three capacitors, each of capacitance \(0.3~\mu \text{F}\) are connected in parallel. This combination is connected with another capacitor of capacitance \(0.1~\mu \text{F}\) in series. Then the equivalent capacitance of the combination is:
1. | \(0.9~\mu\text{F}\) | 2. | \(0.09~\mu\text{F}\) |
3. | \(0.1~\mu\text{F}\) | 4. | \(0.01~\mu\text{F}\) |
1. | \(10 ~\mu \text{F}, ~6~\mu \text{F}\) | 2. | \(8 ~\mu \text{F}, ~8~\mu \text{F}\) |
3. | \(12~\mu \text{F},~ 4~\mu \text{F}\) | 4. | \(1.2~\mu \text{F},~1.8~\mu \text{F}\) |
The equivalent capacitance of the combination shown in the figure is:
1. | \(\frac{C}{2}\) | 2. | \(\frac{3C}{2}\) |
3. | \(3C\) | 4. | \(2C\) |