The potential energy of a particle in a force field is \(U=\frac{A}{r^2}-\frac{B}{r}\) where \(A\) and \(B\) are positive constants and \(r\) is the distance of the particle from the center of the field. For stable equilibrium, the distance of the particle is:
1. \(\frac{B}{A}\) 2. \(\frac{B}{2A}\)
3. \(\frac{2A}{B}\) 4. \(\frac{A}{B}\)
Subtopic:  Potential Energy: Relation with Force |
 78%
From NCERT
AIPMT - 2012
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