The two thigh bones (femurs), each of cross-sectional area \(10\) cm2 support the upper part of a human body of mass \(40\) kg. The average pressure sustained by the femurs is:
1. \(0.2\times 10^{5}\) Nm–2
2. \(2\times10^{5}\) Nm–2
3. \(20\times10^{5}\) Nm–2
4. \(20\times10^{6}\) Nm–2
Pressure on a swimmer \(10\) m below the surface of a lake is:
(Atmospheric pressure= \(1.01\times10^{5}\) Pa, density of water = \(1000\) kg/m3 and \(g=10\) m/s2)
1. \(5\) atm
2. \(4\) atm
3. \(2\) atm
4. \(3\) atm
1. | \(8~\text{km}\) | 2. | \(5~\text{km}\) |
3. | \(7~\text{km}\) | 4. | \(6~\text{km}\) |
1. | \(4.12\times 10^{4}~\text{N}\) | 2. | \(4.12\times 10^{5}~\text{N}\) |
3. | \(5.12\times 10^{5}~\text{N}\) | 4. | \(5.12\times 10^{4}~\text{N}\) |
Two syringes of different cross-sections (without needles) filled with water are connected with a tightly fitted rubber tube filled with water. Diameters of the smaller piston and larger piston are \(1.0\) cm and \(3.0\) cm respectively. Force exerted on the larger piston when a force of \(10\) N is applied to the smaller piston:
1. | \(80\) N | 2. | \(90\) N |
3. | \(10\) N | 4. | \(20\) N |
1. | \(0.67~\text{cm}\) | 2. | \(6.7~\text{cm}\) |
3. | \(67~\text{cm}\) | 4. | \(6.3~\text{cm}\) |
The flow of blood in a large artery of an anesthetised dog is diverted through a Venturi meter. The wider part of the meter has a cross-sectional area equal to that of the artery. A = 8 . The narrower part has an area a = 4 . The pressure drop in the artery is 24 Pa. What is the speed of the blood in the artery?
(Density of blood = )
1. 145 m/s
2. 0.145 m/s
3. 123 m/s
4. 0.123 m/s
A metal block of area \(0.10~\text{m}^{2}\) is connected to a \(0.010~\text{kg}\) mass via a string that passes over an ideal pulley (considered massless and frictionless), as in the figure below. A liquid film with a thickness of \(0.30~\text{mm}\) is placed between the block and the table. When released the block moves to the right with a constant speed of \(0.085~\text{m/s}.\) The coefficient of viscosity of the liquid is:
1. \(4.45 \times 10^{-2}~\text{Pa-s}\)
2. \(4.45 \times 10^{-3}~\text{Pa-s}\)
3. \(3.45 \times 10^{-2}~\text{Pa-s}\)
4. \(3.45 \times 10^{-3}~\text{Pa-s}\)