- 1(current)
Q. No.
1. \(\frac{r}{\sqrt[3]{2}}\)
2. \(\frac{r}{\sqrt[2]{2}}\)
3. \(\frac{2r}{3}\)
4. none of the above
The ratio of the magnitude of electric force to the magnitude of gravitational force for an electron and a proton will be:
(\(m_p=1.67\times10^{-27}~\text{kg}\), \(m_e=9.11\times10^{-31}~\text{kg}\))
1. \(2.4\times10^{39}\)
2. \(2.6\times10^{36}\)
3. \(1.4\times10^{36}\)
4. \(1.6\times10^{39}\)
| 1. | \(\dfrac{-Q}{4}\) | 2. | \(\dfrac{Q}{4}\) |
| 3. | \(\dfrac{-Q}{2}\) | 4. | \(\dfrac{Q}{2}\) |
Consider three charges \(q_1,~q_2,~q_3\) each equal to \(q\) at the vertices of an equilateral triangle of side \(l.\) What is the force on a charge \(Q\) (with the same sign as \(q\)) placed at the centroid of the triangle, as shown in the figure?
| 1. | \(\dfrac{3}{4\pi \epsilon _{0}} \dfrac{Qq}{l^2}\) | 2. | \(\dfrac{9}{4\pi \epsilon _{0}} \dfrac{Qq}{l^2}\) |
| 3. | zero | 4. | \(\dfrac{6}{4\pi \epsilon _{0}} \dfrac{Qq}{l^2}\) |
Consider the charges \(q,~q,\) and \(-q\) placed at the vertices of an equilateral triangle, as shown in the figure. Then the sum of the forces on the three charges is:
1. \(\frac{1}{4\pi \epsilon _{0}}\frac{q^{2}}{l^{2}}\)
2. zero
3. \(\frac{2}{4\pi \epsilon _{0}}\frac{q^{2}}{l^{2}}\)
4. \(\frac{3}{4\pi \epsilon _{0}}\frac{q^{2}}{l^{2}}\)
1. \(v\propto x\)
2. \(v\propto x^{-1/2}\)
3. \(v\propto x^{-1}\)
4. \(v\propto x^{1/2}\)
The accelerations of electron and proton due to the electrical force of their mutual attraction when they are 1 Å (=) apart are respectively: (\(m_p=1.67\times10^{-27}~\text{kg},~m_e=9.11\times10^{-31}~\text{kg}\))
| 1. | \(2.5\times10^{22}\) m/s2, \(2.5\times10^{22}\) m/s2 |
| 2. | \(2.5\times10^{22}\) m/s2, \(1.4\times10^{19}\) m/s2 |
| 3. | \(1.4\times10^{19}\) m/s2, \(2.5\times10^{22}\) m/s2 |
| 4. | \(1.4\times10^{19}\) m/s2, \(1.4\times10^{19}\) m/s2 |
- 1(current)
Q. No.
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