Q. No.An ideal monoatomic gas \(\left(\gamma = \frac{5}{3}\right )\) absorbs 50 cal in an isochoric process. The increase in internal energy of the gas is:
1.
20 cal
2.
Zero
3.
50 cal
4.
30 cal
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The pressure-temperature (P-T) graph for two processes, A and B, in a system is shown in the figure. If and are work done by the gas in process A and B respectively, then:
| 1. | \(W_{1}\) = \(W_{2}\) | 2. | \(W_{1}\) < \(W_{2}\) |
| 3. | \(W_{1}\) > \(W_{2}\) | 4. | \(W_{1}\) = \(-W_{2}\) |
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The variation of molar heat capacity at constant volume with temperature T for a monatomic gas is:
| 1. |  |
2. |  |
| 3. |  |
4. |  |
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When a system is moved from state a to state b along the path acb, it is discovered that the system absorbs 200 J of heat and performs 80 J of work. Along the path adb, heat absorbed Q = 144 J. The work done along the path adb is:
| 1. | 6 J | 2. | 12 J |
| 3. | 18 J | 4. | 24 J |
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If a refrigerator extracts heat 'a' from the cold reservoir and 'b' is the heat released from the hot reservoir, then the work done on the refrigerant (system) is:
1. a + b
2.
3. a
4.
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Heat is supplied to a diatomic gas in an isochoric process. The ratio is: (symbols have usual meanings)
1. 5 : 3
2. 5: 2
3. 1: 1
4. 5: 7
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In the cyclic process shown in the pressure-volume \((P-V)\) diagram, the change in internal energy is equal to:
1.
2.
3.
4. zero
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The work done by an ideal diatomic gas in its sudden expansion is 20 J. The change in the internal energy of the gas will be:
1. 20 J
2. 0 J
3. J
4. J
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A heat engine is working between 200 K and 400 K. The efficiency of the heat engine may be:
1. 20%
2. 40%
3. 50%
4. All of these
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If an ideal gas undergoes two processes at constant volumes as shown in the pressure-temperature (P-T) diagram, then:
1. =
2. >
3. <
4.
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