In the electrochemical cell: 
\(\mathrm{Z n   \left|\right. Z n S O_{4}   \left(\right. 0 . 01   M \left.\right)   \left|\right. \left|\right.   C u S O_{4} \left(\right. 1 . 0   M \left.\right)   \left|\right.   C u}, \)
the emf of this Daniel cell is E1. When the concentration of ZnSO4 is changed to 1.0 M and that of CuSO4 is changed to 0.01 M, the emf changes to E2. From the following, which one is the relationship between E1 and E2
(Given, \(\frac{RT}{F}\) = 0.059)

1. \(\mathrm{E_{1} < E_{2}}\)

2. \(\mathrm{E_{1} > E_{2}}\)

3. \(\mathrm{E_{2} = 0 \neq E_{1}}\)

4. \(\mathrm{E_{1} = E_{2}}\)

Subtopic:  Electrode & Electrode Potential | Nernst Equation |
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The electrode potential for Mg electrode varies according to the equation

\(E_{Mg^{2+}/Mg}\ = \ E_{Mg^{2+}/Mg}^{o} \ - \ \frac{0.059}{2}log\frac{1}{[Mg^{2+}]}\) 

The graph of EMg2+ / Mg vs log [Mg2+] among the following is:

1.    2.  
3.    4.  
Subtopic:  Nernst Equation |
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Consider the following cell reaction 

2Fe(s) + O2(g) + 4H+(aq)  2Fe2+(aq) + 2H2O(l)

E° = 1.67 V, At [Fe2+] = 10-3 M, PO2 = 0.1 atm and pH = 3, the cell potential at 25 °C is : 

1. 1.27 V

2. 1.77 V

3. 1.87 V

4. 1.57 V

Subtopic:  Nernst Equation |
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\(Cu(s)|Cu^{+2}(10^{-3} \ M) \ || \ Ag^{+}(10^{-5} \ M)|Ag(s)\)
if \(E_{Cu^{+2}/Cu}^{o} \ = \ +0.34 \ V\), and \(E_{Ag^{+}/Ag}^{o} \ = \ +0.80 \ V\)
Ecell will be: 

1. 0.46 V
2. \(0.46-\frac{RT}{2F}ln10^{7}\)
3. \(0.46+\frac{RT}{2F}ln10^{7}\)
4. \(0.46-\frac{RT}{2F}ln10^{2}\)

Subtopic:  Nernst Equation |
 53%
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Mg(s) + 2Ag+(0.0001M)  Mg2+(0.130M) + 2Ag(s)

If  EƟ(cell) for the above mentioned cell is 3.17 V, then E(cell) value will be-

(log 13=1.1)

1. 2.87 V
2. 3.08 V
3. 2.96 V
4. 2.68 V

Subtopic:  Nernst Equation |
 52%
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