Linkage maps:

1. always have a total of 100 map units.
2. can be used to pinpoint the precise physical position of a gene on a chromosome.
3. are a genetic map based on recombination frequencies.
4. reflect the frequency of crossing over between X and Y chromosomes.

Subtopic:  Linkage Types |
 71%
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A true breeding red striped tree frog is crossed with a true breeding plain green frog. All progeny have red stripes. This is because:

1. Stripes are dominant to plain green coloration.
2. Striped frogs are camouflaged better.
3. Plain green frogs are easily predated upon.
4. Striped frogs are more common.
Subtopic:  Monohybrid Cross: Further Understanding |
 84%
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A plant breeder is raising many varieties of plants. As a part of the breeding program, he raises pure line varieties by continuous inbreeding over several generations – one with red flowers and another with white flowers. How can Mendel's laws be demonstrated by hybridization between these varieties?

1. Set up a monohybrid cross and determine if your F2 results are predicted by a 3:1 ratio based on the law of segregation.
2. Set up a dihybrid cross and determine if your F2 results are predicted by a 9:3:3:1 ratio based on the law of independent assortment.
3. Set a test cross to demonstrate that your traits breed true.
4. Set up a two-point test cross to demonstrate that your genes are linked.
Subtopic:  Monohybrid Cross: 1 |
 50%
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All the following are mechanisms of sex determination in living organisms except:
1. The Z-W system
2. The X-O system
3. The haplo-diploid system
4. The parthenogenetic system

Subtopic:  Sex Determination: Further Considerations |
 83%
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Pedigree analysis rather than conventional methods are used to study genetic traits because:

I. Number of progeny is limited
II. Choice matings are not possible
III. Sexual dimorphism is seen in humans
 
1. I only 2. II only
3. III only 4. Both I and II
Subtopic:  Pedigree Analysis: Basics |
 78%
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Match the disorder in Column I with the location of the gene causing it in Column II and select the correct option from the codes given:

 

COLUMN I

 

COLUMN II

A.

Sickle cell anaemia

a.

Chromosome 11

B.

Phenylketonuria

b.

Chromosome 12

C.

Cystic fibrosis

c.

Chromosome 7

D.

Huntington’s disease

d.

Chromosome 4

Codes:

A B C D
1. a b c d
2. b a c d
3. a b d c
4. b a d c
Subtopic:  Mendelian Disorders |
 69%
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The pedigree shown below cannot be:

I. Autosomal dominant disorder
II. Autosomal recessive disorder
III. Sex-linked dominant disorder
IV. Sex-linked recessive disorder
V. Holandric disorder
 
1. I, II, and III only 2. I, II, III, and V only
3. I, III, IV, and V only 4. I, II, III, IV and V
Subtopic:  Pedigree Analysis: Basics |
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The recombination frequencies for four different linked genes of Drosophila are shown in the figure:

 

The order of the four genes will be:

1.rb-cn-vg-b2.vg-b-rb-cn
3.cn-rb-b-vg4.b-rb-cn-vg

Subtopic:  Recombination & Gene Mapping |
 55%
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Given below are different levels of organization of genetic material. Arrange them in the correct descending order of their size:

1. Genome, chromosome, gene, nucleotide
2. Gene, chromosome, nucleotide, genome
3. Chromosome, gene, genome, nucleotide
4. Chromosome, genome, nucleotide, gene
Subtopic:  Chromosomal Basis of Inheritance: Introduction |
 69%
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The inheritance of the trait shown in the given pedigree is best explained as a/an:

  

1. Autosomal dominant disorder
2. Autosomal recessive disorder
3. Sex-linked dominant disorder
4. Sex-linked recessive disorder

Subtopic:  Pedigree Analysis: Problem Solving |
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