1. | the stopping potential will be \(0.2\) volts. |
2. | the stopping potential will be \(0.6\) volts. |
3. | the saturation current will be \(6\) mA. |
4. | the saturation current will be \(18\) mA. |
1. | \(\frac{h^{2} m}{2 \lambda^{2}}\) | 2. | \(\frac{2 h m^{2}}{\lambda^{2}}\) |
3. | \(\frac{h^{2} \lambda^{2}}{2 m}\) | 4. | \(\frac{h^{2}}{2 m \lambda^{2}}\) |
1. | ![]() |
2. | ![]() |
3. | ![]() |
4. | ![]() |
On which surface is the electron beam made to fall in the Davisson-Germer experiment?
1. Iron crystals
2. Nickel crystals
3. Gold crystals
4. Cesium crystals
The correct graph between the maximum energy of a photoelectron \(\left(K_{max}\right)\) and the inverse of the wavelength \(\left(\dfrac{1}{\lambda}\right)\) of the incident radiation is given by the curve:
1. | \(A\) | 2. | \(B\) |
3. | \(C\) | 4. | None of these |
If alpha, beta and gamma rays carry the same momentum, which has the longest wavelength?
1. | Alpha rays | 2. | Beta rays |
3. | Gamma rays | 4. | None, all have same wavelength |
The figure shows the variation in photoelectric current \((i)\) with voltage \((V)\) between the electrodes in a photocell for two different radiations. If \(I_a\) and \(I_b\) are the intensities of the incident radiation and \(\nu_a\) and \(\nu_b\) their respective frequencies, then:
1. | \(I_a>I_b,~ \nu_b<\nu_a\) | 2. | \(I_a<I_b, ~\nu_b>\nu_a\) |
3. | \(I_a>I_b,~ \nu_b=\nu_a\) | 4. | \(I_a<I_b, ~\nu_b<\nu_a\) |
The photoelectric effect is used by a photocell to convert:
1. | Change in the frequency of light into a change in electric voltage. |
2. | Change in the intensity of illumination into a change in photoelectric current. |
3. | Change in the intensity of illumination into a change in the work function of the photocathode. |
4. | Change in the frequency of light into a change in the electric current. |