The correct graph between the maximum energy of a photoelectron \(\left(K_{max}\right)\) and the inverse of the wavelength \(\left(\dfrac{1}{\lambda}\right)\) of the incident radiation is given by the curve:
1. | \(A\) | 2. | \(B\) |
3. | \(C\) | 4. | None of these |
If alpha, beta and gamma rays carry the same momentum, which has the longest wavelength?
1. | Alpha rays | 2. | Beta rays |
3. | Gamma rays | 4. | None, all have same wavelength |
The photoelectric effect is used by a photocell to convert:
1. | Change in the frequency of light into a change in electric voltage. |
2. | Change in the intensity of illumination into a change in photoelectric current. |
3. | Change in the intensity of illumination into a change in the work function of the photocathode. |
4. | Change in the frequency of light into a change in the electric current. |
1. | decrease by \(2\) times |
2. | decrease by \(4\) times |
3. | increase by \(4\) times |
4. | increase by \(2\) times |
1. | \(1.00\) | 2. | \(1.02\) |
3. | \(1.04\) | 4. | \(0.98\) |
When photons of energy \(h\nu\) fall on an aluminium plate (of work function \(E_0\)), photoelectrons of maximum kinetic energy \(K\) are ejected.
If the frequency of the radiation is doubled, the maximum kinetic energy of the ejected photoelectrons will be:
1. \(K+ E_0\)
2. \(2K\)
3. \(K\)
4. \(K + h\nu\)
In an experiment of the photoelectric effect, the wavelength of incident radiation is . The wavelength of incident radiation is reduced to rd of initial value and the maximum kinetic energy of photoelectron is observed to be n times the previous value. What will be the threshold wavelength for the metal plate?
1. | \(\dfrac{n-1}{n-3} \lambda \) | 2. | \(\dfrac{n}{n-3} \lambda \) |
3. | \(\dfrac{n-3}{n-1} \lambda \) | 4. | \(\dfrac{n+1}{n-3} \lambda\) |