The frequency of a simple pendulum in a free-falling lift will be:
1. zero
2. infinite
3. can't say
4. finite

Subtopic:  Angular SHM |
 67%
From NCERT
AIPMT - 1999
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When a mass is suspended separately by two different springs, in successive order, then the time period of oscillations is \(t _1\) and \(t_2\) respectively. If it is connected by both springs as shown in the figure below, then the time period of oscillation becomes \(t_0.\) The correct relation between \(t_0,\) \(t_1\) & \(t_2\) is:

1. t02=t12+t22

2. t0-2=t1-2+t2-2

3. t0-1=t1-1+t2-1

4. t0=t1+t2

Subtopic:  Combination of Springs |
 69%
From NCERT
AIPMT - 2002
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When an oscillator completes 100 oscillations, its amplitude is reduced to 13 of the initial value. What will be its amplitude, when it completes 200 oscillations?

1. 18

2. 23

3. 16

4. 19

Subtopic:  Damped Oscillations (OLD NCERT) |
 69%
From NCERT
AIPMT - 2002
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The displacement between the maximum potential energy position and maximum kinetic energy position for a particle executing simple harmonic motion is:
1. \(\pm \frac{a}{2}\)
2. \(+a\)
3. \(\pm a\)
4. \(-1\)

Subtopic:  Energy of SHM |
 74%
From NCERT
AIPMT - 2002
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The time period of a mass suspended from a spring is \(T\). If the spring is cut into four equal parts and the same mass is suspended from one of the parts, then the new time period will be:
1. \(\frac{T}{4}\)
2. \(T\)
3. \(\frac{T}{2}\)
4. \(2T\)

Subtopic:  Spring mass system |
 73%
From NCERT
AIPMT - 2003
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A particle of mass \(m\) oscillates with simple harmonic motion between points \(x_1\) and \(x_2\), the equilibrium position being \(O\). Its potential energy is plotted. It will be as given below in the graph:

1. 2.
3. 4.
Subtopic:  Energy of SHM |
 84%
From NCERT
AIPMT - 2003
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In case of a forced vibration, the resonance wave becomes very sharp when the:
1. Damping force is small
2. Restoring force is small
3. Applied periodic force is small
4. Quality factor is small

Subtopic:  Forced Oscillations (OLD NCERT) |
 64%
From NCERT
AIPMT - 2003
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The potential energy of a simple harmonic oscillator, when the particle is halfway to its endpoint, will be:
1. \(\frac{2E}{3}\)
2. \(\frac{E}{8}\)
3. \(\frac{E}{4}\)
4. \(\frac{E}{2}\)

Subtopic:  Energy of SHM |
 80%
From NCERT
AIPMT - 2003
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A body oscillates with SHM according to the equation (in SI units), \(x= 5\cos\left[2\pi t +\frac{\pi}{4}\right].\) At \(t = 1.5\) s, acceleration of the body will be:
1. \(140 \text{ cm} / \text{s}^2 \) 2. \(160 \text{ m} / \text{s}^2 \)
3. \(140 \text{ m} / \text{s}^2 \) 4. \(14 \text{ m} / \text{s}^2\)
Subtopic:  Linear SHM |
 58%
From NCERT
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A spring elongates by a length 'L' when a mass 'M' is suspended to it. Now a tiny mass 'm' is attached to the mass 'M' and then released. The new time period of oscillation will be:

1.  \(2 \pi \sqrt{\frac{\left(\right. M   +   m \left.\right) l}{Mg}}\)

2. \(2 \pi \sqrt{\frac{ml}{Mg}}\)

3. \(2 \pi \sqrt{L   /   g}\)

4. \(2 \pi \sqrt{\frac{Ml}{\left(\right. m   +   M \left.\right) g}}\)

Subtopic:  Spring mass system |
 59%
From NCERT
AIPMT - 1999
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