Q. No.In the circuit shown below, what will be the readings of the voltmeter and ammeter?
1. \(800~\text{V}, 2~\text{A}\)
2. \(300~\text{V}, 2~\text{A}\)
3. \(220~\text{V}, 2.2~\text{A}\)
4. \(100~\text{V}, 2~\text{A}\)
1. \(R + 2\pi f L\)
2. \(\sqrt{R^{2} + 4 \pi^{2} f^{2} L^{2}}\)
3. \(\sqrt{R^{2} + L^{2}}\)
4. \(\sqrt{R^{2} + 2 \pi f L}\)
In an \(LCR\) circuit, the potential difference between the terminals of the inductance is \(60\) V, between the terminals of the capacitor is \(30\) V and that between the terminals of the resistance is \(40\) V. The supply voltage will be equal to:
1. \(50\) V
2. \(70\) V
3. \(130\) V
4. \(10\) V
In a series \(RLC\) circuit, potential differences across \(R,L\) and \(C\) are \(30\) V, \(60\) V and \(100\) V respectively, as shown in the figure. The emf of the source (in volts) will be:
1. \(190\)
2. \(70\)
3. \(50\)
4. \(40\)
1. \(LC\)
2. \((LC)^{\frac{-1}{2}}\)
3. \(\left(\frac{L}{C}\right)^{\frac{-1}{2}}\)
4. \(\frac{C}{L}\)
A series AC circuit has a resistance of \(4~\Omega\) and an inductor of reactance \(3~\Omega\). The impedance of the circuit is \(z_1\). Now when a capacitor of reactance \(6~\Omega\) is connected in series with the above combination, the impedance becomes \(z_2\). Then \(\frac{z_1}{z_2}\) will be:
1. \(1:1\)
2. \(5:4\)
3. \(4:5\)
4. \(2:1\)
| 1. | \(V_r=V_L>V_C\) |
| 2. | \(V_R \neq V_L=V_C\) |
| 3. | \(V_R \neq V_L \neq V_C\) |
| 4. | \(V_R=V_C \neq V_L\) |
An ideal resistance \(R\), ideal inductance \(L\), ideal capacitance \(C\), and AC voltmeters \(V_1, V_2, V_3~\text{and}~V_4 \)
| 1. | Reading in \(V_3\) = Reading in \(V_1\) |
| 2. | Reading in \(V_1\) = Reading in \(V_2\) |
| 3. | Reading in \(V_2\) = Reading in \(V_4\) |
| 4. | Reading in \(V_2\) = Reading in \(V_3\) |
1. \(35\)
2. \(20\)
3. \(15\)
4. \(25\)
| 1. | \(\frac{R}{4}\) |
| 2. | \(\frac{R}{2}\) |
| 3. | \(R\) |
| 4. | Cannot be found with the given data |
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