A charge \(q\) is placed in a uniform electric field \(E.\) If it is released, then the kinetic energy of the charge after travelling distance \(y\) will be:

1. \(qEy\) 2. \(2qEy\)
3. qEy2 4. qEy

Subtopic:  Electric Field |
 76%
From NCERT
AIPMT - 1998
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The electric field at the equator of a dipole is \(E.\) If the strength of the dipole and distance are now doubled, then the electric field will be:

1. \(E/2\) 2. \(E/8\)
3. \(E/4\) 4. \(E\)
Subtopic:  Electric Dipole |
 66%
From NCERT
AIPMT - 1998
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In Millikan oil drop experiment, a charged drop falls with a terminal velocity \(v\). If an electric field \(E\) is applied vertically upwards it moves with terminal velocity \(2v\) in upward direction. If electric field reduces to \(\frac{E}{2}\) then its terminal velocity will be:
1. \(\frac{v}{2}\)
2. \(v\)
3. \(\frac{3v}{2}\)
4. \(2v\)

Subtopic:  Electric Field |
From NCERT
AIPMT - 1999
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The figure shows electric field lines in which an electric dipole \(p\) is placed as shown. Which of the following statements is correct?
                         

1. The dipole will not experience any force.
2. The dipole will experience a force towards the right.
3. The dipole will experience a force towards the left.
4. The dipole will experience a force upwards.

Subtopic:  Electric Dipole |
From NCERT
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The acceleration of an electron due to the mutual attraction between the electron and a proton when they are \(1.6~\mathring{A}\) apart is:
\(\frac{1}{4 \pi \varepsilon_0}=9 \times 10^9~ \text{Nm}^2 \text{C}^{-2}\) )

1. \( 10^{24} ~\text{m/s}^2\) 2 \( 10^{23} ~\text{m/s}^2\)
3. \( 10^{22}~\text{m/s}^2\) 4. \( 10^{25} ~\text{m/s}^2\)
Subtopic:  Coulomb's Law |
 75%
From NCERT
NEET - 2020
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The electric field at a point on the equatorial plane at a distance \(r\) from the centre of a dipole having dipole moment \(\overrightarrow{P}\) is given by:
(\(r\gg\) separation of two charges forming the dipole, \(\varepsilon_{0} =\) permittivity of free space) 

1. \(\overrightarrow{E}=\frac{\overrightarrow{P}}{4\pi \varepsilon _{0}r^{3}}\)  2. \(\overrightarrow{E}=\frac{2\overrightarrow{P}}{\pi \varepsilon _{0}r^{3}}\)
3. \(\overrightarrow{E}=-\frac{\overrightarrow{P}}{4\pi \varepsilon _{0}r^{2}}\) 4. \(\overrightarrow{E}=-\frac{\overrightarrow{P}}{4\pi \varepsilon _{0}r^{3}}\)
Subtopic:  Electric Dipole |
 62%
From NCERT
NEET - 2020
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Refer to the arrangement of charges in the figure and a Gaussian surface of radius \(R\) with \(Q\) at the centre. Then:
         

a. total flux through the surface of the sphere is \(\frac{-Q}{\varepsilon_0}\).
b. field on the surface of the sphere is \(\frac{-Q}{4\pi \varepsilon_0 R^2}.\)
c. flux through the surface of the sphere due to \(5Q\) is zero.
d. field on the surface of the sphere due to \(-2Q\) is the same everywhere.

Choose the correct statement(s): 
1. (a) and (d)
2. (a) and (c)
3. (b) and (d)
4. (c) and (d)

Subtopic:  Gauss's Law |
 71%
From NCERT
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If there were only one type of charge in the universe, then,
a. sE.dS0 on any surface.
b. sE.dS=0 if the charge is outside the surface.
c. sE.dS could not be defined.
d. sE.dS=qε0 if charges of magnitude \(q\) were inside the surface.
Choose the correct statement(s):
1. (a) and (d)
2. (a) and (c)
3. (b) and (d)
4. (c) and (d)
Subtopic:  Gauss's Law |
 72%
From NCERT
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Two point dipoles of dipole moment \(\vec{p}_{1}\) and \(\vec{p}_{2}\) are at a distance \(x\) from each other and \(\vec{p}_{1} \left|\right| \vec{p}_{2}\). The force between the dipole is:
1. \(\frac{1}{4 π\varepsilon_{0}} \frac{4 p_{1} p_{2}}{x^{4}}\)
2. \(\frac{1}{4 π\varepsilon_{0}} \frac{3 p_{1} p_{2}}{x^{3}}\)
3. \(\frac{1}{4π\varepsilon_{0}} \frac{6 p_{1} p_{2}}{x^{4}}\)
4. \(\frac{1}{4 π\varepsilon_{0}} \frac{8 p_{1} p_{2}}{x^{4}}\)

Subtopic:  Electric Dipole |
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A hollow metal sphere of radius \(R\) is uniformly charged. The electric field due to the sphere at a distance \(r\) from the centre:

1. decreases as \(r\) increases for \(r<R\) and for \(r>R\).
2. increases as \(r\) increases for \(r<R\) and for \(r>R\).
3. is zero as \(r\) increases for \(r<R\), decreases as \(r\) increases for \(r>R\).
4. is zero as \(r\) increases for \(r<R\), increases as \(r\) increases for \(r>R\).
Subtopic:  Gauss's Law |
 81%
From NCERT
NEET - 2019
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