There are two heaters \(A\) and \(B.\) Heater \(A\) takes time \(t_1\) to boil a given quantity of water, while \(B\) takes time \(t_2\) to boil the same quantity of water across same supply voltage. If the two heaters are connected in series, time taken by this combination to boil the same quantity of water will be:
1. \(\large\frac{t_1t_2}{t_1+t_2}\)
2. \(t_1+t_2\)
3. \({\large\frac12}(t_1+t_2)\)
4. \(\large\frac{t_1t_2}{2(t_1+t_2)}\)