In the organic compound
$$CH₂=CH–CH₂–CH₂–C≡CH, which pair of hybridized orbitals is involved in forming the C₂–C₃ bond?
1. sp – ${\mathrm{sp}}^2$ 

2. sp – ${\mathrm{sp}}^3$

3. ${\mathrm{sp}}^2$ – ${\mathrm{sp}}^3$

4. ${\mathrm{sp}}^3$ – ${\mathrm{sp}}^3$

Any type of chromatography shares which of the following characteristic?

1. Use of molecules that are soluble in water.

2. Use of inert carrier gas.

3. Calculation of R_f value for the molecule separated.

4. Use of a mobile and a stationary phase.

The number of σ and π bonds in the molecule $C_6{H}_6$ are -

The number of σ and π bonds in the molecule $C_6{H}_{12}$ are:

1. 7 = (${\sigma }_{C-C})$ , 11 =  $\left({\sigma }_{C-H}\right)$, and 0= π 

2. 6 = (${\sigma }_{C-C})$ , 12 =  $\left({\sigma }_{C-H}\right)$, and 0= π 

3. 12 = (${\sigma }_{C-C})$ , 6 =  $\left({\sigma }_{C-H}\right)$, and 1= π 

4. 5 = (${\sigma }_{C-C})$ , 13 =  $\left({\sigma }_{C-H}\right)$, and 1= π 

The number of σ and π bonds in the molecule ${\mathrm{CH}}_2{\mathrm{Cl}}_2$ are -

1.  2 = (${\sigma }_{C-Cl})$ , 1= $\left({\sigma }_{C-H}\right)$ , and 1= π

2. 2 = (${\sigma }_{C-Cl})$ , 2= $\left({\sigma }_{C-H}\right)$ , and 0= π

3. 2 = (${\sigma }_{C-Cl})$ , 1= $\left({\sigma }_{C-H}\right)$ , and 1= π

4. 2 = (${\sigma }_{C-Cl})$ , 1= $\left({\sigma }_{C-H}\right)$ , and 1= π

Chlorine atom can be classified as:

$\stackrel{1}{C}{H}_2$ $=\stackrel{2}{C}=O$

The correct hybridization states of carbon atoms in the above compound are - 

The correct hybridization states of carbon atoms marked as 1,2,3 in the following compound are:
\({ }^1 \mathrm{CH}_3-\mathrm{ }^2{C} \mathrm{H}={}^3{\mathrm{C}} \mathrm{H}_2 \)

The correct hybridization states of carbon atoms in the following compound are - $\stackrel{1}{\mathrm{\hspace{0.17em}\; \hspace{0.17em}\; C}}{H}_2=\stackrel{2}{C}H-\stackrel{3}{C}\equiv N$
 

The correct hybridization states of carbon atoms in C₆H_{6 (cyclic compound)} is/are:

1.  sp² 

2. sp

3. sp³

4.  All of the above