A solution is obtained by mixing 300 g of 25 % solution and 400 g of 40 % solution by mass. The mass percentage of solute in the resulting solution is:
1. 33.5 %
2. 36.5 %
3. 37.4 %
4. 32.5 %
An antifreeze solution is prepared from 222.6 g of ethylene glycol (C2H6O2) and 200 g of water. The molality of the solution would be:
1. | 6.9 m | 2. | 17.9 m |
3. | 29.9 m | 4. | 21.9 m |
A sample of drinking water was contaminated with chloroform. The level of contamination was 15 ppm (by mass). The mass percent of chloroform is:
1.
2.
3.
4.
The type of molecular interactions in a solution of alcohol and water is:
1. | Electrostatic interaction | 2. | London dispersion forces |
3. | Hydrogen bonding | 4. | Ion-dipole interaction |
A solution of glucose (M.W= 180 g mol-1) in water is 10 % w/w. The mole fraction of each component in the solution is:
1. | Mole fraction of glucose - 0.44; mole fraction of water - 0.56 |
2. | Mole fraction of glucose - 0.056; mole fraction of water - 0.944 |
3. | Mole fraction of glucose - 0.011; mole fraction of water - 0.99 |
4. | Mole fraction of glucose - 0.36; mole fraction of water - 0.64 |
The density of 68 % nitric acid by mass in an aqueous solution is 1.504 g mL-1. The molarity of the acid solution would be:
1. | 15.24 M | 2. | 16.23 M |
3. | 14.52 M | 4. | 13.45 M |
1. | \(\text X_{\text{mole fraction}}=\frac{\text n_{\text{solute}}}{\text n_{\text{solution}}}\) |
2. | \(\text{Molarity}=\frac{\text{amount of solute (g)}}{\text{volume of solution (mL)}}\) |
3. | \(\text{Molality}=\frac{\text{Number of mole of solute}}{\text{amount of solvent (kg)}}\) |
4. | \(\text{Mass percentage}=\frac{\text{mass of the component in the solution}}{\text{Total mass of the solution}}\times100 \) |
The example of gas in a solid type solution is:
1. Solution of hydrogen in palladium.
2. Ethanol dissolved in water.
3. Camphor vapours in N2 gas.
4. Amalgams.
Type of solution | Example |
a. Solid in gas | i. Aerated water |
b. Gas in liquid | ii. Smoke |
c. Liquid in solid | iii. Solution of hydrogen in palladium |
d. Gas in solid | iv. Amalgams |
a | b | c | d | |
1. | i | iii | iv | ii |
2. | ii | i | iv | iii |
3. | iii | i | iv | ii |
4. | iv | i | ii | iii |
To minimize the painful effects accompanying deep sea diving, oxygen diluted with less soluble helium gas is used as breathing gas by the divers. This is an example of the application of:
1. | Raoult's law | 2. | Henry's law |
3. | Ideal gas Equation | 4. | All of the above |