The figure shows some of the equipotential surfaces. The magnitude and direction of the electric field are given by:

                

1.	\(200~\text{V/m},\) making an angle \(120^\circ\) with the \(x\text-\)axis
2.	\(100~\text{V/m},\) pointing towards the negative \(x\text-\)axis
3.	\(200~\text{V/m},\) making an angle \(60^\circ\) with the \(x\text-\)axis
4.	\(100~\text{V/m},\) making an angle \(30^\circ\) with the \(x\text-\)axis

In the given figure if \(V = 4~\text{volt}\) each plate of the capacitor has a surface area of\(10^{-2}~\text{m}^2\) and the plates are$\mathrm{}$ \(0.1\times10^{-3}~\text{m}\)apart, then the number of excess electrons on the negative plate is:

Two thin dielectric slabs of dielectric constants \(K_1~\text{and}~K_2(K_{1} < K_{2})\) are inserted between plates of a parallel capacitor, as shown in the figure. The variation of the electric field \(E\) between the plates with distance \(d\) as measured from the plate \(P\) is correctly shown by:  
   

1.		2.
3.		4.

An electric dipole of moment \(p\) is placed in an electric field of intensity \(E\). The dipole acquires a position such that the axis of the dipole makes an angle \(\theta\) with the direction of the field. Assuming that the potential energy of the dipole to be zero when \(\theta = 90^{\circ},\) the torque and the potential energy of the dipole will respectively be:

The equivalent capacitance of the following arrangement is:
               
1. \(18~\mu \text{F}\)
2. \(9~\mu \text{F}\)
3. \(6~\mu \text{F}\)
4. \(12~\mu \text{F}\)

Two capacitors of capacitance \(6~\mu\text{F}\) and \(3~\mu\text{F}\) are connected in series with battery of \(30~\text{V}\). The charge on \(3~\mu\text{F}\) capacitor is:
          
1. \( 3 ~\mu\text{C}\)
2. \( 1.5 ~\mu\text{C}\)
3. \( 60~\mu\text{C}\)
4. \( 900~\mu\text{C}\)

Two concentric metallic spherical shells \(A\) and \(B\) of radii \(a\) and \(b\) respectively \((b>a)\) are arranged such that outer shell is earthed and inner shell is charged to \(Q\). Charge on the outer surface of outer shell will be:
1. \(- \frac{Q a}{b}\)
2. \(Q \left[1 - \frac{a}{b}\right]\)
3. \(-Q\)
4. zero

The equivalent capacitance across \(A\) and \(B\) in the given figure is: