The electric and the magnetic field, associated with an electromagnetic wave, propagating along the \(+z\text-\)axis, can be represented by:

1.	\(\left[{E}={E}_0 \hat{k}, {B}={B}_0 \hat{i}\right]\)
2.	\(\left[E={E}_0 \hat{j}, ~{B}={{B}_0} \hat{j}\right]\)
3.	\(\left[{E}={E}_0 \hat{j}, ~{B}={B}_0 \hat{k}\right]\)
4.	\(\left[{E}={E}_0 \hat{i}, ~{B}={{B}_0} \hat{j}\right]\)

The velocity of electromagnetic radiation in a medium of permittivity \(\varepsilon_0\) and permeability \(\mu_0\) is given by:
1. \(\sqrt{\frac{\varepsilon_{0}}{\mu_{0}}}\)
2. \(\sqrt{\mu_0 \varepsilon_0}\)
3. \(\frac{1}{\sqrt{\mu_0 \varepsilon_0}}\)
4. \(\sqrt{\frac{\mu_{0}}{\varepsilon_{0}}}\)

The electric field associated with an electromagnetic wave in vacuum is given by \(E=40 \cos \left(k z-6 \times 10^8 t\right)\), where \(E\), \(z\), and \(t\) are in volt/m, meter, and second respectively. The value of the wave vector \(k\) would be:
1. \(2~\text{m}^{-1}\)
2. \(0.5~\text{m}^{-1}\)
3. \(6~\text{m}^{-1}\)
4. \(3~\text{m}^{-1}\)     

An EM wave is propagating in a medium with a velocity \(\overrightarrow{{v}}={v} \hat{i}\). The instantaneous oscillating electric field of this EM wave is along the \(+y\) axis. The direction of the oscillating magnetic field of the EM wave will be along:
1. \(-z \text-\)direction
2. \(+z \text-\) direction
3. \(-y \text-\) direction
4.  \(+y \text-\) direction

Out of the following options which one can be used to produce a propagating electromagnetic wave?

The velocity of electromagnetic wave is parallel to:
1. \(\vec{B} \times \vec{E}\)
2. \(\vec{E} \times \vec{B}\)
3. \(\vec {E}\)
4. \(\vec{B}\) 

The charge of a parallel plate capacitor is varying as \(q = q_{0} \sin\omega t\). Find the magnitude of displacement current through the capacitor. 
(Plate Area = \(A\), separation of plates = \(d\))
1. \(q_{0}\cos \left(\omega t \right)\)
2. \(q_{0} \omega \sin\omega t\)
3. \(q_{0} \omega \cos \omega t\)
4. \(\frac{q_{0} A \omega}{d} \cos \omega t\)

The energy density of the electromagnetic wave in vacuum is given by the relation:

1. $\frac{1}{2}.\frac{E^2}{{\epsilon }_0}+\frac{B^2}{2{\mu }_0}$ 

2. $\frac{1}{2}{\epsilon }_0{E}^2+\frac{1}{2}{\mu }_0{B}^2$

3. $\frac{E^2+B^2}{C}$

4. $\frac{1}{2}{\epsilon }_0{E}^2+\frac{B^2}{2{\mu }_0}$

The S.I. unit of displacement current is: