- 1(current)
Q. No.Light is:
| 1. | a wave phenomenon |
| 2. | a particle phenomenon |
| 3. | both particle and wave phenomenon |
| 4. | none of the above |
Subtopic: Â Diffraction |
 90%
From NCERT
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A parallel beam of light of wavelength \(\lambda\) is incident normally on a narrow slit. A diffraction pattern is formed on a screen placed perpendicular to the direction of the incident beam. At the second minimum of the diffraction pattern, the phase difference between the rays coming from the two edges of the slit is:
| 1. | \(2 \pi\) | 2. | \(3 \pi\) |
| 3. | \(4 \pi\) | 4. | \( \pi \lambda\) |
Subtopic: Â Diffraction |
 58%
From NCERT
NEET - 2013
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The width of the central maximum of the diffraction pattern of a single slit of width \(1~\text{mm}\) equals the width of the slit itself, when the screen is \(1~\text m\) away from it. The wavelength of light used equals:
| 1. | \(250~\text{nm}\) | 2. | \(500~\text{nm}\) |
| 3. | \(1000~\text{nm}\) | 4. | \(2000~\text{nm}\) |
Subtopic: Â Diffraction |
 68%
From NCERT
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Light of wavelength \(\lambda\) falls perpendicularly onto a single slit of width \(d\). A diffraction maximum is formed at \(P\) on a faraway screen placed parallel to plane of the slit. The first diffraction minimum is formed at \(Q,\) as shown on the screen. Let \(C\) be a 'point' so that it divides the slit \(AB\) in the ratio \(\dfrac{AC}{CB}=\dfrac12,\) i.e. \(AC\) represents the upper \(\dfrac13^{rd}\) of the slit. The total amplitude of the oscillation arriving from \(AC\) at \(Q\) is \(A_1\) and from \(CB\) at \(Q\) is \(A_2\).
Then:
1. \(2 A_{1}=A_{2}\)
2. \(A_{1}=2 A_{2}\)
3. \(\sqrt{2} A_{1}=A_{2}\)
4. \(A_{1}=A_{2}\)
Then:
1. \(2 A_{1}=A_{2}\)
2. \(A_{1}=2 A_{2}\)
3. \(\sqrt{2} A_{1}=A_{2}\)
4. \(A_{1}=A_{2}\)
Subtopic: Â Diffraction |
From NCERT
To view explanation, please take trial in the course.
NEET 2026 - Target Batch - Vital
Hints
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- 1(current)
Q. No.
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