Assertion (A): | A glass tube partially filled with water represents an open organ pipe. |
Reason (R): | The open end corresponds to an antinode and the end in contact with water, to a node. |
1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are True and (R) is not the correct explanation of (A). |
3. | (A) is True but (R) is False. |
4. | (A) is False but (R) is True. |
1. | \(3:1\) | 2. | \(1:2\) |
3. | \(2:1\) | 4. | \(1:3\) |
1. | \(8:9\) | 2. | \(9:7\) |
3. | \(9:8\) | 4. | \(7:9\) |
A string of length \(l\) is fixed at both ends and is vibrating in second harmonic. The amplitude at antinode is \(2\) mm. The amplitude of a particle at a distance \(l/8\) from the fixed end is:
1. \(2\sqrt2~\text{mm}\)
2. \(4~\text{mm}\)
3. \(\sqrt2~\text{mm}\)
4. \(2\sqrt3~\text{mm}\)
1. | \(420\) Hz | 2. | \(440\) Hz |
3. | \(484\) Hz | 4. | \(512\) Hz |
The length of the string of a musical instrument is \(90\) cm and has a fundamental frequency of \(120\) Hz. Where should it be pressed to produce a fundamental frequency of \(180\) Hz?
1. | \(75\) cm | 2. | \(60\) cm |
3. | \(45\) cm | 4. | \(80\) cm |
The fundamental frequency in an open organ pipe is equal to the third harmonic of a closed organ pipe. If the length of the closed organ pipe is \(20~\text{cm}\), the length of the open organ pipe is:
1. \(13.2~\text{cm}\)
2. \(8~\text{cm}\)
3. \(12.5~\text{cm}\)
4. \(16~\text{cm}\)
The two nearest harmonics of a tube closed at one end and open at the other end are \(220\) Hz and \(260\) Hz. What is the fundamental frequency of the system?
1. \(20\) Hz
2. \(30\) Hz
3. \(40\) Hz
4. \(10\) Hz
The second overtone of an open organ pipe has the same frequency as the first overtone of a closed pipe \(L\) meter long. The length of the open pipe will be:
1. \(L\)
2. \(2L\)
3. \(\frac{L}{2}\)
4. \(4L\)
1. | \(100~\text{cm}\) | 2. | \(150~\text{cm}\) |
3. | \(200~\text{cm}\) | 4. | \(66.7~\text{cm}\) |