- 1(current)
Q. No.A square current-carrying loop is suspended in a uniform magnetic field acting in the plane of the loop. If the force on one arm of the loop is \( \overrightarrow{F}\), what will be the net force on the remaining three arms of the loop?
| 1. | \(3 \overrightarrow{F}\) | 2. | \(- \overrightarrow{F}\) |
| 3. | \(-3 \overrightarrow{F}\) | 4. | \( \overrightarrow{F}\) |
Subtopic: Â Current Carrying Loop: Force & Torque |
 82%
From NCERT
AIPMT - 2010
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A closed-loop \(PQRS\) carrying a current is placed in a uniform magnetic field. If the magnetic forces on segments \(PS\), \(SR\), and \(RQ\) are \(F_1, F_2~\text{and}~F_3\) respectively, and are in the plane of the paper and along the directions shown,
then which of the following forces acts on the segment \(QP\)?
1. \(F_{3} - F_{1} - F_{2}\)
2. \(\sqrt{\left(F_{3} - F_{1}\right)^{2} + F_{2}^{2}}\)
3. \(\sqrt{\left(F_{3} - F_{1}\right)^{2} - F_{2}^{2}}\)
4. \(F_{3} - F_{1} + F_{2}\)
Subtopic: Â Current Carrying Loop: Force & Torque |
 78%
From NCERT
AIPMT - 2008
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A circular loop with a radius of \(20\) cm is placed in a uniform magnetic field \(B=2T\) in the \(XY\) plane as shown in the figure. If the loop carries a current of \(i = 1~\text{A}\), then the magnitude of torque acting on the loop will be:
1. \(0.25\) N-m
2. \(5.2\) N-m
3. \(2.5\) N-m
4. \(0.52\) N-m
1. \(0.25\) N-m
2. \(5.2\) N-m
3. \(2.5\) N-m
4. \(0.52\) N-m
Subtopic: Â Current Carrying Loop: Force & Torque |
 71%
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
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Links
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
- 1(current)
Q. No.
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