If \(\Delta Q\) is the heat flowing out of a system, \(\Delta W\) is the work done by the system on its surroundings, and \(\Delta U\) is the decrease in internal energy of the system, then the first law of thermodynamics can be stated as:
1. \(\Delta Q=\Delta U+\Delta W\)
2. \(\Delta U=\Delta Q+\Delta W\)
3. \(\Delta U=\Delta Q-\Delta W\)
4. \(\Delta U+\Delta Q+\Delta W=0\)
Subtopic:  First Law of Thermodynamics |
 59%
From NCERT
Please attempt this question first.
Hints
Please attempt this question first.

A thermodynamic process involving a system takes place with \(100\) J of heat being rejected to the environment and an increase of \(20\) J of internal energy. Then,
1. work done by the system is \(120\) J.
2. work done on the system is \(120\) J.
3. work done by the system is \(80\) J.
4. work done on the system is \(80\) J.
Subtopic:  First Law of Thermodynamics |
 67%
From NCERT
Please attempt this question first.
Hints
Please attempt this question first.

If an average person jogs, he produces \(14.5 \times10^3\) cal/min. This is removed by the evaporation of sweat. The amount of sweat evaporated per minute (assuming \(1\) kg requires \(580 \times10^3\) cal for evaporation) is:

1. \(0.25\) kg 2. \(0.50\) kg
3. \(0.025\) kg 4. \(0.20\) kg
Subtopic:  First Law of Thermodynamics |
 68%
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

advertisementadvertisement

\(1~\text g\) of water of volume \(1~\text{cm}^3\) at \(100^\circ \text{C}\) is converted into steam at the same temperature under normal atmospheric pressure \(\approx 1\times10^{5}~\text{Pa}.\) The volume of steam formed equals \(1671~\text{cm}^3.\) If the specific latent heat of vaporization of water is \(2256~\text{J/g},\) the change in internal energy is:
1. \(2423~\text J\) 
2. \(2089~\text J\) 
3. \(167~\text J\) 
4. \(2256~\text J\) 

Subtopic:  First Law of Thermodynamics |
 66%
From NCERT
NEET - 2019
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
Links
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

The internal energy of a gas is given by \(U=\frac32PV.\) The gas expands in such a way that its internal energy (initially \(U_0\)) remains constant throughout the process, but its volume changes from \(V_0\) to \(2V_0.\) The heat supplied to the gas equals:
1. \(U_0\mathrm{ln}(2)\) 2. \(\dfrac12U_0~\mathrm{ln}(2)\)
3. \(\dfrac13U_0~\mathrm{ln}(2)\) 4. \(\dfrac23U_0~\mathrm{ln}(2)\)
Subtopic:  First Law of Thermodynamics |
 66%
From NCERT
Please attempt this question first.
Hints
Please attempt this question first.

The first law of thermodynamics is a statement of:
1. conservation of heat
2. conservation of work
3. conservation of momentum
4. conservation of energy

Subtopic:  First Law of Thermodynamics |
 87%
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

advertisementadvertisement

Consider the process on a system shown in the figure. During the process, the work done by the system:
           

1. continuously increases
2. continuously decreases
3. first increases then decreases
4. first decreases then increases


 

Subtopic:  Work Done by a Gas |
 59%
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

An ideal gas goes from the state \(i\) to the state \(f\) as shown in figure given below. The work done by the gas during the process,

   
 

1. is positive
2. is negative
3. is zero
4. cannot be obtained from this information
Subtopic:  Work Done by a Gas |
 65%
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

For the given cycle, the work done during the isobaric process is:

            
1. \(200\) J
2. zero
3. \(400\) J
4. \(600\)
Subtopic:  Work Done by a Gas |
 53%
From NCERT
NEET - 2023
Please attempt this question first.
Hints
Please attempt this question first.

advertisementadvertisement

The molar specific heat at a constant pressure of an ideal gas is \(\dfrac{7}{2}R.\) The ratio of specific heat at constant pressure to that at constant volume is:

1. \(\dfrac{7}{5}\) 2. \(\dfrac{8}{7}\)
3. \(\dfrac{5}{7}\) 4. \(\dfrac{9}{7}\)
Subtopic:  Molar Specific Heat |
 77%
From NCERT
AIPMT - 2006
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
Links
To view explanation, please take trial in the course.
NEET 2025 - Target Batch