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Q. No.A balloon ascends upward with a constant upward velocity \(5\) m/s. At the same time it is being pushed to the right by the wind with a speed that is proportional to its height \((y)\): \(v_\text{right}=2y\)
where the units are in SI. The acceleration of the balloon is:
1. zero
2. \(10\) m/s2 to right
3. \(5\) m/s2 to right
4. \(10\) m/s2 upward
where the units are in SI. The acceleration of the balloon is:
1. zero
2. \(10\) m/s2 to right
3. \(5\) m/s2 to right
4. \(10\) m/s2 upward
Subtopic: Â Acceleration |
From NCERT
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Hints
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Mark the correct statements for a particle going on a straight line:
| (a) | if the velocity and acceleration have opposite sign, the object is slowing down. |
| (b) | if the position and velocity have opposite sign, the particle is moving towards the origin. |
| (c) | if the velocity is zero at an instant, the acceleration should also be zero at that instant. |
| (d) | if the velocity is zero for a time interval, the acceleration is zero at any instant within the time interval. |
Choose the correct option:
| 1. | (a), (b) and (c) | 2. | (a), (b) and (d) |
| 3. | (b), (c) and (d) | 4. | all of these |
Subtopic: Â Acceleration |
 64%
From NCERT
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When brakes are applied to a moving vehicle, the distance it travels before stopping is called stopping distance. It is an important factor for road safety and depends on the initial velocity \({v_0}\) and the braking capacity, or deceleration, \(-a\) that is caused by the braking. Expression for stopping distance of a vehicle in terms of \({v_0}\) and \(a\) is:
| 1. | \(\dfrac{{v_o}^2}{2a}\) | 2. | \(\dfrac{{v_o}}{2a}\) |
| 3. | \(\dfrac{{v_o}^2}{a}\) | 4. | \(\dfrac{2a}{{v_o}^2}\) |
Subtopic: Â Acceleration |
 84%
From NCERT
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A particle moves a distance \(x\) in time \(t\) according to equation \(x=(t+5)^{-1}.\) The acceleration of the particle is proportional to:
1. (velocity)\(3/2\)
2. (distance)\(2\)
3. (distance)\(-2\)
4. (velocity)\(2/3\)
Subtopic: Â Acceleration |
 70%
From NCERT
AIPMT - 2010
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A particle moves along a straight line such that its velocity is proportional to the square root of its displacement. Its acceleration is:
| 1. | zero |
| 2. | constant |
| 3. | proportional to time |
| 4. | proportional to displacement |
Subtopic: Â Acceleration |
 69%
From NCERT
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