Which of the following complexes formed by Cu⁺⁺ ions is most stable?

The colour of the coordination compounds depends on the crystal field splitting. What will be the correct order of absorption of the wavelength of light in the visible region for the complexes?

\(1. \ \left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}>\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}>\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+} \\ 2. \ \left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}>\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}>\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+} \\ 3. \ \left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}>\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}>\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-} \\ 4. \ \left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}>\left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}>\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\)

When 0.1 mol CoCl₃(NH₃)₅ is treated with an excess of AgNO₃, 0.2 mol of AgCl is obtained. The conductivity of the solution will correspond to:

1. 1:3 electrolyte

2. 1:2 electrolyte

3. 1:1 electrolyte

4. 3:1 electrolyte

When 1 mole of ${\mathrm{CrCl}}_{3}6{\mathrm{H}}_2\mathrm{O}$ is treated with excess of ${\mathrm{AgNO}}_3,$ 3 moles of ${\mathrm{AgCl}}_{}$ are obtained. The formula of the complex is:

1. [CrCl₃(H₂O)₃].3H₂O
2. [CrCl₂(H₂O)₄]Cl.2H₂O
3. [CrCl₃(H₂O)₅]Cl₂.H₂O
4. [Cr(H₂O)₆]Cl₃

The correct IUPAC name of [Pt(NH₃)${}_2$Cl${}_2$] is:

1. Diamminedichloridoplatinum (ll)

2. Diamminedichloridoplatinum (lV)

3. Diamminedichloridoplatinum (0)

4. Dichloridodiammineplatinum (lV)

The stabilization of coordination compounds due to chelation is called the chelate effect. Which of the following is the most stable complex species?

Indicate the complex ion that shows geometrical isomerism:
1. [Cr(H₂O)₄ Cl₂]⁺
2. [Pt(NH₃)₃ Cl]
3. [Co(NH₃)₆]³⁺
4. [Co(CN)₆]^3-

The CFSE for octahedral${\left[\mathrm{ \; C}oC{l}_6\right]}^{4-}$ is 18,000 cm${}^{-1}$ . The CFSE for tetrahedral will be \(\mathrm{CoCl}_4{ }^{2-}\):${\left[\right]}^{}$\(\mathrm{CoCl}_4{ }^{2-}\)

1. 6000 cm${}^{-1}$

2. 16,000 cm${}^{-1}$

3. 18,000 cm${}^{-1}$

4. 8,000 cm${}^{-1}$

Due to the presence of ambidentate ligands coordination compounds show isomerism. Palladium complexes of the type $\mathrm{Pd}{( {\mathrm{C}}_6{\mathrm{H}}_5 )}_2(\mathrm{NCS}{)}_2$ and $\left[Pd{\left(C_6{H}_5\right)}_2{\left(SCN\right)}_2\right]$ are:

1. Linkage isomers   
2. Coordination isomers
3. Ionization isomers 
4. Geometrical isomers

The compounds [Co(SO${}_4$ (NH${}_3$)${}_5$ ]Br and [Co(SO${}_4$ (NH${}_3$)${}_5$] Cl classified as: