A nucleus with mass number \(240\) breaks into fragments each of mass number \(120\). The binding energy per nucleon of unfragmented nuclei is \(7.6~\text{MeV}\) while that of fragments is \(8.5~\text{MeV}\). The total gain in the binding energy in the process is:
1. \(804~\text{MeV}\)
2. \(216~\text{MeV}\)
3. \(0.9~\text{MeV}\)
4. \(9.4~\text{MeV}\)
1. | \(\beta^{+}, ~\alpha, ~\beta^{-}\) | 2. | \(\beta^{-}, ~\alpha, ~\beta^{+}\) |
3. | \(\alpha, ~\beta^{-},~\beta^{+}\) | 4. | \(\alpha, ~\beta^{+},~\beta^{-}\) |
What happens to the mass number and the atomic number of an element when it emits \(\gamma\text{-}\)radiation?
1. | mass number decreases by four and atomic number decreases by two. |
2. | mass number and atomic number remain unchanged. |
3. | mass number remains unchanged while the atomic number decreases by one. |
4. | mass number increases by four and the atomic number increases by two. |
1. | \({ }_{12}^{22} \mathrm{Mg}\) | 2. | \({ }_{11}^{23} \mathrm{Na}\) |
3. | \({ }_{10}^{23} \mathrm{Ne}\) | 4. | \(_{10}^{22}\textrm{Ne}\) |
1. | \(25:16\) | 2. | \(1:1\) |
3. | \(4:5\) | 4. | \(5:4\) |
The energy equivalent of \(0.5\) g of a substance is:
1. \(4.5\times10^{13}\) J
2. \(1.5\times10^{13}\) J
3. \(0.5\times10^{13}\) J
4. \(4.5\times10^{16}\) J