If the radius of \(_{13}^{27}\mathrm{Al}\) nucleus is taken to be \(\mathrm{R}_{\mathrm{Al}},\) then the radius of \(_{53}^{125}\mathrm{Te}\) nucleus is near:
1. \(\left(\frac{53}{13}\right) ^{\frac{1}{3}}~\mathrm{R_{Al}}\)
2. \(\frac{5}{3}~\mathrm{R_{Al}}\)
3. \(\frac{3}{5}~\mathrm{R_{Al}}\)
4. \(\left(\frac{13}{53}\right)~\mathrm{R_{Al}}\)

If the nuclear radius of \(^{27}\text{Al}\) is \(3.6\) Fermi, the approximate nuclear radius of \(^{64}\text{Cu}\) in Fermi is:
1. \(2.4\)
2. \(1.2\)
3. \(4.8\)
4. \(3.6\)

Two nuclei have their mass numbers in the ratio of \(1:3.\) The ratio of their nuclear densities would be:
1. \(1:3\)
2. \(3:1\)
3. \((3)^{1/3}:1\)
4. \(1:1\)