An increase in the temperature of a gas-filled in a container would lead to:
| 1. | decrease in the intermolecular distance. |
| 2. | increase in its mass. |
| 3. | increase in its kinetic energy. |
| 4. | decrease in its pressure. |
To find out the degree of freedom, the correct expression is:
1. \(f=\frac{2}{\gamma -1}\)
2. \(f=\frac{\gamma+1}{2}\)
3. \(f=\frac{2}{\gamma +1}\)
4. \(f=\frac{1}{\gamma +1}\)
Diatomic molecules like hydrogen have energies due to both translational as well as rotational motion. The equation in kinetic theory \(PV = \dfrac{2}{3}E,\) \(E\) is:
| 1. | the total energy per unit volume. |
| 2. | only the translational part of energy because rotational energy is very small compared to translational energy. |
| 3. | only the translational part of the energy because during collisions with the wall, pressure relates to change in linear momentum. |
| 4. | the translational part of the energy because rotational energies of molecules can be of either sign and its average over all the molecules is zero. |
The ratio of the average translatory kinetic energy of \(\mathrm{He}\) gas molecules to \(\mathrm{O_2}\)
1. \(\frac{25}{21}\)
2. \(\frac{21}{25}\)
3. \(\frac{3}{2}\)
4. \(1\)
What is the graph between volume and temperature in Charle's law?
1. An ellipse
2. A circle
3. A straight line
4. A parabola
The mean free path for a gas, with molecular diameter \(d\) and number density \(n,\) can be expressed as:
| 1. | \( \dfrac{1}{\sqrt{2} n \pi {d}^2} \) | 2. | \( \dfrac{1}{\sqrt{2} n^2 \pi {d}^2} \) |
| 3. | \(\dfrac{1}{\sqrt{2} n^2 \pi^2 d^2} \) | 4. | \( \dfrac{1}{\sqrt{2} n \pi {d}}\) |
Without change in temperature, a gas is forced in a smaller volume. Its pressure increases because its molecules:
| 1. | strike the unit area of the container wall more often. |
| 2. | strike the unit area of the container wall at a higher speed. |
| 3. | strike the unit area of the container wall with greater force. |
| 4. | have more energy. |
If at a pressure of \(10^6\) dyne/cm2, one gram of nitrogen occupies \(2\times10^4\) c.c. volume, then the average energy of a nitrogen molecule in erg is:
| 1. | \(14\times10^{-13}\) | 2. | \(10\times10^{-12}\) |
| 3. | \(10^{6}\) | 4. | \(2\times10^{6}\) |
The translational kinetic energy of \(n\) moles of a diatomic gas at absolute temperature \(T\) is given by:
1. \(\frac{5}{2}nRT\)
2. \(\frac{3}{2}nRT\)
3. \(5nRT\)
4. \(\frac{7}{2}nRT\)
The translational kinetic energy of oxygen molecules at room temperature is \(60~\text J.\) Their rotational kinetic energy will be?
1. \(40~\text J\)
2. \(60~\text J\)
3. \(50~\text J\)
4. \(20~\text J\)