The mean free path for a gas, with molecular diameter \(d\) and number density \(n,\) can be expressed as:
1. \( \frac{1}{\sqrt{2} n \pi \mathrm{d}^2} \)
2. \( \frac{1}{\sqrt{2} n^2 \pi \mathrm{d}^2} \)
3. \(\frac{1}{\sqrt{2} n^2 \pi^2 d^2} \)
4. \( \frac{1}{\sqrt{2} n \pi \mathrm{d}}\)
If the mean free path of atoms is doubled , then the pressure of the gas will become:
1. P/4
2. P/2
3. P/8
4. P
If the pressure in a closed vessel is reduced by drawing out some gas, the mean free path of the molecules:
1. | decreases |
2. | increases |
3. | remains unchanged |
4. | increases or decreases according to the nature of the gas |