The moment of inertia of a uniform circular disc of radius '\(R\)' and mass '\(M\)' about an axis touching the disc at its diameter and normal to the disc will be:
1. \(\frac{3}{2} M R^{2}\)
2. \(\frac{1}{2} M R^{2}\)
3. \(M R^{2}\)
4. \(\frac{2}{5} M R^{2}\)

Subtopic:  Moment of Inertia |
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A man of \(50~\text{kg}\) mass is standing in a gravity-free space at a height of \(10~\text m\) above the floor. He throws a stone of \(0.5~\text{kg}\) mass downwards with a speed of \(2~\text{ms}^{-1}.\) When the stone reaches the floor, the distance of the man above the floor will be: 
1. \(9.9~\text m\) 2. \(10.1~\text m\)
3. \(10~\text m\) 4. \(20~\text m\)
Subtopic:  Center of Mass |
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NEET - 2010
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Three-point masses each of mass \(m,\) are placed at the vertices of an equilateral triangle of side \(a.\) The moment of inertia of the system through a mass \(m\) at \(O\) and lying in the plane of \(COD\) and perpendicular to \(OA\) is:

                   

1. \(2ma^2\) 2. \({2 \over 3}ma^2\)
3. \({5 \over 4}ma^2\) 4. \({7 \over 4}ma^2\)
Subtopic:  Moment of Inertia |
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If a body is moving in a circular path with decreasing speed, then: (symbols have their usual meanings):

1.  \(\overset{\rightarrow}{r} . \overset{\rightarrow}{\omega}=0\) 
2.  \(\overset{\rightarrow}{\tau} . \overset{\rightarrow}{v}=0\) 
3.  \(\overset{\rightarrow}{a} . \overset{\rightarrow}{v}<0\) 
4.  All of these

Subtopic:  Rotational Motion: Kinematics |
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A solid sphere of mass \(M\) and the radius \(R\) is in pure rolling with angular speed \(\omega\) on a horizontal plane as shown in the figure. The magnitude of the angular momentum of the sphere about the origin \(O\) is:
                     

1. \(\frac{7}{5} M R^{2} \omega\)
2. \(\frac{3}{2} M R^{2} \omega\)
3. \(\frac{1}{2} M R^{2} \omega\)
4. \(\frac{2}{3} M R^{2} \omega\)

Subtopic:  Angular Momentum |
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A boy is standing on a disc rotating about the vertical axis passing through its centre. He pulls his arms towards himself, reducing his moment of inertia by a factor of m. The new angular speed of the disc becomes double its initial value. If the moment of inertia of the boy is I0 , then the moment of inertia of the disc will be:

1.  2I0m

2.  I01-2m

3.  I01-1m

4.  I02m

Subtopic:  Angular Momentum |
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Four masses are joined to light circular frames as shown in the figure. The radius of gyration of this system about an axis passing through the center of the circular frame and perpendicular to its plane would be:
(where '\(a\)' is the radius of the circle)
                        
1. \(\frac{a}{\sqrt{2}}\)
2. \(\frac{a}{{2}}\)
3. \(a\)
4. \(2a\)

Subtopic:  Moment of Inertia |
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Four thin rods, each of mass \(m\) and the length \(L,\) form a square. The moment of inertia on any side of the square is:

               
1. \(\frac{5}{3}mL^2\)
2. \(4mL^2\)
3. \(\frac{1}{4}mL^2\)
4. \(\frac{2}{3}mL^2\)

Subtopic:  Moment of Inertia |
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A force \(\vec F = \left(2 \hat{i} + 3 \hat{j} + 4 \hat{k} \right) \text{N}\) is acting at point \((2~\text{m}, -3~\text{m}, 6~\text{m}).\) Find the torque of this force about a point whose position vector is \(\left(2 \hat{i}+ 5\hat {j}+ 3\hat {k}\right) \text{m}\).
1. \(\vec{\tau}=(-17 \hat{\mathrm{i}}+6 \hat{\mathrm{j}}+4 \widehat{\mathrm{k}})\) N-m
2. \(\vec{\tau}=(-17 \hat{\mathrm{i}}+6 \hat{\mathrm{j}}-4 \widehat{\mathrm{k}}) \) N-m
3. \(\vec{\tau}=(17 \hat{\mathrm{i}}-6 \hat{\mathrm{j}}+4 \widehat{\mathrm{k}})\) N-m
4. \(\vec{\tau}=(-41 \hat{\mathrm{i}}+6 \hat{\mathrm{j}}+16 \hat{\mathrm{k}})\) N-m
Subtopic:  Torque |
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In the three figures, each wire has a mass M, radius R and a uniform mass distribution. If they form part of a circle of radius R, then about an axis perpendicular to the plane and passing through the centre (shown by crosses), their moment of inertia is in the order:

 

1.  IA > IB >  IC

2.  IA = IB = IC

3.  IA < IB < IC

4.  IA < IC < IB

Subtopic:  Moment of Inertia |
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