In a two-dimensional motion, instantaneous speed \(v_0\) is a positive constant. Then which of the following is necessarily true?
1. | The acceleration of the particle is zero. |
2. | The acceleration of the particle is increasing. |
3. | The acceleration of the particle is necessarily in the plane of motion. |
4. | The particle must be undergoing a uniform circular motion. |
The \(x\) and \(y\) coordinates of the particle at any time are \(x = 5t-2t^2\) and \(y=10t\) respectively, where \(x\) and \(y\) are in metres and \(t\) is in seconds. The acceleration of the particle at \(t=2\) s is:
1. | \(0\) | 2. | \(5\) m/s2 |
3. | \(-4\) m/s2 | 4. | \(-8\) m/s2 |
1. | \(5\sqrt2\) m/s2 SE | 2. | \(\dfrac{5}{\sqrt2}\) m/s2 SE |
3. | \(5\sqrt2\) m/s2 NE | 4. | \(\dfrac{5}{\sqrt2}\) m/s2 NE |
Assertion (A): | In a two-dimensional motion, there are two accelerations acting on the particle. |
Reason (R): | Both the components of velocity, i.e., horizontal and vertical, in case of free fall keeps on changing with respect to time. |
1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
3. | (A) is True but (R) is False. |
4. | Both (A) and (R) are False. |
The position vector of a particle \(\vec{r}\) as a function of time \(t\) (in seconds) is \(\vec{r}=(3t) \hat{i}+(2t^2) \hat{j}\) m. The initial acceleration of the particle is:
1. | \(2\) m/s2 | 2. | \(3\) m/s2 |
3. | \(4\) m/s2 | 4. | \(\mathrm{zero}\) |