Q. No.1. front tyre
2. road
3. rear tyre
4. brakes
| Assertion (A): | Friction is a consequence of electromagnetic interaction between two bodies in contact. |
| Reason (R): | The electromagnetic force is a fundamental force. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | Both (A) and (R) are False. |
(Assume the gravitational field strength is \(10~\text{Nkg}^{-1}\), that air resistance is negligible and that the orientation of the book does not change.)
| 1. | \(25.0~\text{m/s}^2\) | 2. | \(12.5~\text{m/s}^2\) |
| 3. | \(50.0~\text{m/s}^2\) | 4. | \(20.0~\text{m/s}^2\) |
A block of mass \(3\) kg is placed on a rough surface \((\mu=0.2)\) and a variable force acts on it. Variation of acceleration of block with time is correctly shown by the graph:
| 1. |  |
2. |  |
| 3. |  |
4. |  |
| 1. | \(0.1\) | 2. | \(0.2\) |
| 3. | \(0.3\) | 4. | \(0.4\) |
1. \(5\) N
2. \(6\) N
3. \(5.88\) N
4. \(8\) N
| 1. | \(50\) ms–2 | 2. | \(1.2\) ms–2 |
| 3. | \(150\) ms–2 | 4. | \(1.5\) ms–2 |
A body of mass \(m\) is kept on a rough horizontal surface (coefficient of friction = \(\mu).\) A horizontal force is applied to the body, but it does not move. The resultant of normal reaction and the frictional force acting on the object is given by \(\vec {F}\) where:
1. \(|{\vec {F}}| = mg+\mu mg\)
2. \(|\vec {F}| =\mu mg\)
3. \(|\vec {F}| \le mg\sqrt{1+\mu^2}\)
4. \(|\vec{F}| = mg\)
| 1. | \( \dfrac{15\sqrt{3}}{2} \) N | 2. | \(7 \sqrt{3}\) N |
| 3. | \(10\) N | 4. | none of these |
The coefficient of static friction, \(\mu_s,\) between block A of mass \(2\) kg and the table as shown in the figure is \(0.2\). What would be the maximum mass value of block B so that the two blocks do not move? The string and the pulley are assumed to be smooth and massless. (Take \(g=10\) m/s2 )
1. \(4.0\) kg
2. \(0.2\) kg
3. \(0.4\) kg
4. \(2.0\) kg
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