- 1(current)
Q. No.Two bodies of mass \(m\) and \(9m\) are placed at a distance \(R.\) The gravitational potential on the line joining the bodies where the gravitational field equals zero, will be:
(\(G=\) gravitational constant)
1. \(-\dfrac{20~Gm}{R}\)
2. \(-\dfrac{8~Gm}{R}\)
3. \(-\dfrac{12~Gm}{R}\)
4. \(-\dfrac{16~Gm}{R}\)
(\(G=\) gravitational constant)
1. \(-\dfrac{20~Gm}{R}\)
2. \(-\dfrac{8~Gm}{R}\)
3. \(-\dfrac{12~Gm}{R}\)
4. \(-\dfrac{16~Gm}{R}\)
Subtopic: Â Gravitational Potential |
 57%
From NCERT
NEET - 2023
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Two heavy spheres each of mass \(100~\text{kg}\) and radius \(0.10~\text m,\) are placed \(1.0~\text m\) apart on a horizontal table. What is the gravitational potential at the midpoint of the line joining the centres of the spheres?
| 1. | \(2.67\times10^{-8}~\text{J/kg}\) | 2. | Zero |
| 3. | \(6.67\times10^{-9}~\text{J/kg}\) | 4. | \(3.71\times10^{-8}~\text{J/kg}\) |
Subtopic: Â Gravitational Potential |
 53%
From NCERT
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NEET 2026 - Target Batch - Vital
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NEET 2026 - Target Batch - Vital
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