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Q. No.Two bodies of mass \(m\) and \(9m\) are placed at a distance \(R.\) The gravitational potential on the line joining the bodies where the gravitational field equals zero, will be:
(\(G=\) gravitational constant)
1. \(-\frac{20~Gm}{R}\)
2. \(-\frac{8~Gm}{R}\)
3. \(-\frac{12~Gm}{R}\)
4. \(-\frac{16~Gm}{R}\)
(\(G=\) gravitational constant)
1. \(-\frac{20~Gm}{R}\)
2. \(-\frac{8~Gm}{R}\)
3. \(-\frac{12~Gm}{R}\)
4. \(-\frac{16~Gm}{R}\)
Subtopic: Gravitational Potential |
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From NCERT
NEET - 2023
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Four particles, each of mass \(m,\) are kept at the four corners of a square of side \(l\) each. The amount of work done to separate these particles for no interaction between them will be:
1. \(\dfrac{4Gm^2}{l}\)
2. \(-{\dfrac{Gm^2} {l}}(4+\sqrt 2)\)
3. \({\dfrac{Gm^2}{l}}(4+\sqrt 2)\)
4. \(\dfrac{{Gm}^2}{l}\left(1+\dfrac{1}{\sqrt{2}}\right)\)
1. \(\dfrac{4Gm^2}{l}\)
2. \(-{\dfrac{Gm^2} {l}}(4+\sqrt 2)\)
3. \({\dfrac{Gm^2}{l}}(4+\sqrt 2)\)
4. \(\dfrac{{Gm}^2}{l}\left(1+\dfrac{1}{\sqrt{2}}\right)\)
Subtopic: Gravitational Potential |
From NCERT
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Two heavy spheres each of mass \(100\) kg and radius \(0.10\) m are placed \(1.0\) m apart on a horizontal table. What is the gravitational potential at the midpoint of the line joining the centres of the spheres?
| 1. | \(2.67\times10^{-8}\) J kg–1 | 2. | \(0\) |
| 3. | \(6.67\times10^{-9}\) J kg–1 | 4. | \(3.71\times10^{-8}\) J kg–1 |
Subtopic: Gravitational Potential |
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From NCERT
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A body is projected vertically upwards from the surface of the earth with a velocity equal to one-third of escape velocity. The maximum height attained by the body will be:
(Take the radius of earth \(=6400\) km and \(g=10\) ms–2 )
1. \(800\) km
2. \(1600\) km
3. \(2133\) km
4. \(4800\) km
(Take the radius of earth \(=6400\) km and \(g=10\) ms–2 )
1. \(800\) km
2. \(1600\) km
3. \(2133\) km
4. \(4800\) km
Subtopic: Gravitational Potential |
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From NCERT
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