The gravitational potential energy of a particle of mass \(m\) at a distance \(r\) from the centre of the earth is given by:
(\(M=\) mass of the earth, \(G=\) gravitational constant):
1. \(\dfrac{GMm}{r}\) 2. \(\dfrac{-GMm}{r}\)
3. \(\dfrac{GM}{r}\) 4. \(\dfrac{-GM}{r}\)
Subtopic:  Gravitational Potential Energy |
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Given below are two statements: 

Assertion (A): When a body is raised from the surface of the earth, its potential energy increases.
Reason (R): Potential energy of a body on the surface of the earth is zero.
  
1. Both (A) and (R) are True and (R) is the correct explanation of (A).
2. Both (A) and (R) are True but (R) is not the correct explanation of (A).
3. (A) is True but (R) is False.
4. Both (A) and (R) are False.
Subtopic:  Gravitational Potential Energy |
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An object of mass \(m\) is placed at a height \(R_{e}\) from the surface of the earth. What is the increase in potential energy of the object if the height of the object is increased to \(2R_{e}\) from the surface? (\(R_{e}:\) Radius of the earth)
1. \({\dfrac{1}{3}{mgR}_{e}}\)
2. \({\dfrac{1}{6}{mgR}_{e}}\)
3. \({\dfrac{1}{2}{mgR}_{e}}\)
4. \({\dfrac{1}{4}{mgR}_{e}}\)
Subtopic:  Gravitational Potential Energy |
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A particle of mass \(m\) starts from rest at a large distance from the planet of mass \(M,\) reaches the planet only under gravitational attraction and passes through smooth tunnel through its centre. The gravitational potential energy of the particle at the centre will be: 
(\(R\) is the radius of the planet)
1. \(-\dfrac{GMm}{2R}\) 2. \(-\dfrac{GMm}{R}\)
3. \(-\dfrac{3GMm}{2R}\) 4. \(-\dfrac{3GMm}{R}\)
Subtopic:  Gravitational Potential Energy |
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The work done to raise a mass \(m\) from the surface of the earth to a height \(h\), which is equal to the radius of the earth, is:
1. \(\dfrac{3}{2}mgR\)
2. \(mgR\)
3. \(2mgR\)
4. \(\dfrac{1}{2}mgR\)  
Subtopic:  Gravitational Potential Energy |
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The potential energy of a system of four particles placed at the vertices of a square of side \(l\) (as shown in the figure below) and the potential at the centre of the square, respectively, are:

                       

1. \(- 5 . 41 \dfrac{Gm^{2}}{l}\) and \(0\)

2. \(0\) and \(- 5 . 41 \dfrac{Gm^{2}}{l}\) 

3. \(- 5 . 41 \dfrac{Gm^{2}}{l}\) and \(- 4 \sqrt{2} \dfrac{Gm}{l}\)

4. \(0\) and \(0\)

Subtopic:  Gravitational Potential Energy |
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Two uniform solid spheres of equal radii \({R},\) but mass \({M}\) and \(4M\) have a centre to centre separation \(6R,\) as shown in the figure. The two spheres are held fixed. A projectile of mass \(m\) is projected from the surface of the sphere of mass \(M\) directly towards the centre of the second sphere. The expression for the minimum speed \(v\) of the projectile so that it reaches the surface of the second sphere is:

1. \(\left(\dfrac{3 {GM}}{5 {R}}\right)^{1 / 2}\)
2. \(\left(\dfrac{2 {GM}}{5 {R}}\right)^{1 / 2}\)
3. \(\left(\dfrac{3 {GM}}{2 {R}}\right)^{1 / 2}\)
4. \(\left(\dfrac{5 {GM}}{3 {R}}\right)^{1 / 2}\)
Subtopic:  Gravitational Potential Energy |
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Assuming that the gravitational potential energy of an object at infinity is zero, the change in potential energy (final - initial) of an object of mass \(m\) when taken to a height \(h\) from the surface of the earth (of radius \(R\) and mass \(M\)), is given by:

1. \(-\frac{GMm}{R+h}\) 2. \(\frac{GMmh}{R(R+h)}\)
3. \(mgh\) 4. \(\frac{GMm}{R+h}\)
Subtopic:  Gravitational Potential Energy |
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The gravitational potential energy of a particle of mass \(m\) increases by \(mgh,\) when it is raised through a height \(h\) in a uniform gravitational field "\(g\)". If a particle of mass \(m\) is raised through a height \(h\) in the earth's gravitational field (\(g\): the field on the earth's surface) and the increase in gravitational potential energy is \(U\), then:
1. \(U > mgh\)
2. \(U < mgh\)
3. \(U = mgh\)
4. any of the above may be true depending on the value of \(h,\) considered relative to the radius of the earth.
Subtopic:  Gravitational Potential Energy |
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