Three capacitors of capacitances \(2~\text{pF},\) \(3~\text{pF},\) and \(4~\text{pF}\) are connected in parallel. The charge on the \(4~\text{pF}\) capacitor, if the combination is connected to a \(100~\text V\) supply, is:
1. \(4\times10^{-10}~\text C\)
2. \(3\times10^{-9}~\text C\)
3. \(2\times10^{-10}~\text C\)
4. \(1\times10^{-9}~\text C\)
The equivalent capacitance of the given circuit is:
1. \(\dfrac{C}{2}\)
2. \(C\)
3. \(2C\)
4. \(4C\)
In the circuit shown in the figure initially, key \(K_1\) is closed and key \(K_2\) is open. Then \(K_1\) is opened and \(K_2\) is closed (order is important).
(Take \(Q_1\) and \(Q_2\) as charges on \(C_1\) and \(C_2\) and \(V_1\) and \(V_2\) as voltage respectively.)
Then,
(a) | charge on \(C_1\) gets redistributed such that \(V_1 =V_2\) |
(b) | charge on \(C_1\) gets redistributed such that \(Q'_1= Q'_2\) |
(c) | charge on \(C_1\) gets redistributed such that \(C_1V_1+C_2V_2= C_1E\) |
(d) | charge on \(C_1\) gets redistributed such that \(Q'_1+Q'_2=Q\) |
Choose the correct option:
1. (a), (d)
2. (a), (b), (c)
3. (b), (d)
4. (a), (b), (c), (d)
Three identical capacitors are connected as follows:
Which of the following shows the order of increasing capacitance (smallest first)?
1. | (3), (2), (1) | 2. | (1), (2), (3) |
3. | (2), (1), (3) | 4. | (2), (3), (1) |
Two capacitors of capacitance \(6~\mu\text{F}\) and \(3~\mu\text{F}\) are connected in series with battery of \(30~\text{V}\). The charge on \(3~\mu\text{F}\) capacitor at a steady state is:
1. \( 3 ~\mu\text{C}\)
2. \( 1.5 ~\mu\text{C}\)
3. \( 60~\mu\text{C}\)
4. \( 900~\mu\text{C}\)