- 1(current)
Q. No.The current in a simple series circuit is \(5.0\) A. When an additional resistance of \(2.0\) \(\Omega\) is inserted, the current drops to \(4.0\) A. The original resistance of the circuit was:
| 1. | \(1.25\) \(\Omega\) | 2. | \(8\) \(\Omega\) |
| 3. | \(10\) \(\Omega\) | 4. | \(20\) \(\Omega\) |
Subtopic: Â Combination of Resistors |
 84%
From NCERT
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\(10\) resistors, each of resistance \(R\) are connected in series to a battery of \(E\) and negligible internal resistance. Then those are connected in parallel to the same battery, the current is increased \(n\) times. The value of \(n\) is:
| 1. | \(1000\) | 2. | \(10\) |
| 3. | \(100\) | 4. | \(1\) |
Subtopic: Â Combination of Resistors |
 66%
From NCERT
NEET - 2023
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A wire of length \('l'\) and resistance \(100 ~\Omega\) is divided into \(10\) equal parts. The first \(5\) parts are connected in series while the next \(5\) parts are connected in parallel. The two combinations are again connected in series. The resistance of this final combination is:
| 1. | \(52~ \Omega\) | 2. | \(55~ \Omega\) |
| 3. | \(60 ~\Omega\) | 4. | \(26~ \Omega\) |
Subtopic: Â Combination of Resistors |
 65%
From NCERT
NEET - 2024
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Each branch in the following circuit has a resistance \(R\).
The equivalent resistance of the circuit between points \(A\) and \(B\) is:
| 1. | \(R\) | 2. | \(2R\) |
| 3. | \(4R\) | 4. | \(8R\) |
Subtopic: Â Combination of Resistors |
From NCERT
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What will be the equivalent resistance between the two points \(A\) and \(D\) as shown in the figure?
1. \(10~\Omega\)
2. \(20~\Omega\)
3. \(30~\Omega\)
4. \(40~\Omega\)
1. \(10~\Omega\)
2. \(20~\Omega\)
3. \(30~\Omega\)
4. \(40~\Omega\)
Subtopic: Â Combination of Resistors |
 80%
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The equivalent resistance \(R_{AB}\) between points \(A\) and \(B\) in the given network is:
1. \(1R\)
2. \({\dfrac35}R\)
3. \({\dfrac78}R\)
4. \({\dfrac58}R\)
1. \(1R\)
2. \({\dfrac35}R\)
3. \({\dfrac78}R\)
4. \({\dfrac58}R\)
Subtopic: Â Combination of Resistors |
 73%
From NCERT
NEET - 2024
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In the circuit shown, The current through \(R_{4}~(I_{4})\) and \(R_{5}~(I_{5})\) is:
| 1. | \(I_4=\dfrac{24}{55}~\text{A},~\text{and} ~I_5 = \dfrac{96}{55}~\text{A}\) |
| 2. | \(I_4=\dfrac{96}{55}~\text{A},~\text{and} ~I_5 = \dfrac{24}{55}~\text{A}\) |
| 3. | \(I_4=\dfrac{24}{37}~\text{A},~\text{and}~ I_5 = \dfrac{96}{37}~\text{A}\) |
| 4. | \(I_4=\dfrac{96}{37}~\text{A},~\text{and} ~I_5 = \dfrac{24}{37}~\text{A}\) |
Subtopic: Â Combination of Resistors |
 78%
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The effective resistance between points \(\mathrm{P}\) and \(\mathrm{Q}\) of the electrical circuit shown in the figure is:
1. \(2 R r /(R+r)\)
2. \(8 R(R+r) /(3 R+r)\)
3. \(2r+4R\)
4. \(5R/2+2r\)
1. \(2 R r /(R+r)\)
2. \(8 R(R+r) /(3 R+r)\)
3. \(2r+4R\)
4. \(5R/2+2r\)
Subtopic: Â Combination of Resistors |
 85%
From NCERT
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- 1(current)
Q. No.
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