- 1(current)
Q. No.\(18\) cells each having same emf are connected in series with some cells being wrongly connected. This arrangement of battery is connected in series with an ammeter and two identical cells which are in series. Current of \(3~\text{A}\) is drawn when cells and battery support each other and current of \(2~\text{A}\) is drawn when cells and battery oppose each other. The number of wrongly connected cells are:
1. \(1\)
2. \(2\)
3. \(3\)
4. \(4\)
1. \(1\)
2. \(2\)
3. \(3\)
4. \(4\)
Subtopic: Grouping of Cells |
From NCERT
Please attempt this question first.
Hints
Please attempt this question first.
Two batteries of emf and internal resistances respectively are connected in parallel as shown in the figure.
| 1. | The equivalent emf of the two cells is between |
| 2. | The equivalent emf is smaller than |
| 3. | The is given by always |
| 4. | is independent of internal resistances |
Subtopic: Grouping of Cells |
58%
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Two hundred cells of the same emf \(E\) and same internal resistance \(r\) are connected in series in the same order without external resistance. The potential drop across \(50\) cells is found to be:
1. \(50E\)
2. \(150E\)
3. \(200E\)
4. zero
1. \(50E\)
2. \(150E\)
3. \(200E\)
4. zero
Subtopic: Grouping of Cells |
From NCERT
Please attempt this question first.
Hints
Please attempt this question first.
Two cells having emfs \(3\) V and \(2\) V are connected in parallel and they give an emf of \(0.5\) V in the same sense as \(3\) V \(-\) cell. The internal resistances of the cells are \(r_1\) and \(r_2\) respectively. If one cell is reversed, their combined emf becomes \(2.5\) V. The ratio of their internal resistances \(\Big(\dfrac{r_1}{r_2}\Big) \) is:
1. \(1\)
2. \(\dfrac12\)
3. \(\dfrac21\)
4. \(\sqrt2\)
1. \(1\)
2. \(\dfrac12\)
3. \(\dfrac21\)
4. \(\sqrt2\)
Subtopic: Grouping of Cells |
67%
From NCERT
Please attempt this question first.
Hints
Please attempt this question first.
\(n\) identical cells each of emf \(E\) and internal resistance \(r\) are connected in series. An external resistance \(R\) is connected in series to this combination to form a loop. The current through \(R\) is:
| 1. | \(\dfrac{n E}{R+r}\) | 2. | \(\dfrac{n E}{n R+r}\) |
| 3. | \( \dfrac{n E}{R+n r}\) | 4. | \(\dfrac{E}{R+n r}\) |
Subtopic: Grouping of Cells |
85%
From NCERT
Please attempt this question first.
Hints
Please attempt this question first.
A battery consists of a variable number \(n\) of identical cells having equal internal resistance connected in series. The terminals of the battery are short-circuited and the current \(I\) measured. Which one of the graphs below shows the correct relationship between \(I\) and \(n?\)
| 1. |  |
2. |  |
| 3. |  |
4. |  |
Subtopic: Grouping of Cells |
74%
From NCERT
Please attempt this question first.
Hints
Please attempt this question first.
For the circuit shown in the figure, the current \(I\) will be:
| 1. | \(0.75~\text{A}\) | 2. | \(1~\text{A}\) |
| 3. | \(1.5~\text{A}\) | 4. | \(0.5~\text{A}\) |
Subtopic: Grouping of Cells |
81%
From NCERT
NEET - 2020
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
Links
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
- 1(current)
Q. No.
© 2024 GoodEd Technologies Pvt. Ltd.