- 1(current)
Q. No.Maxwell's modified form of Ampere's Circuital law is:
| 1. | \(\oint{\vec{{B}}}.d\vec{s} ={0}\) |
| 2. | \(\oint{\vec{{B}}}.d\vec{l} ={\mathit{\mu}}_{0}{I}\) |
| 3. | \(\oint{\vec{B}}.d\vec{l}={{\mu}}_{0}{I}+\dfrac{1}{{\varepsilon }_{0}}\dfrac{dq}{dt}\) |
| 4. | \(\oint{\vec{B}}.d\vec{l} ={{\mu}}_{0}{I}+{{\mu}}_{0}{\varepsilon}_{0}\dfrac{d{{\phi}}_{E}}{dt}\) |
Subtopic: Â Maxwell's Equations |
 76%
From NCERT
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Maxwell's equation \(\oint\vec E\cdot d\vec l=\dfrac{-d\phi_B}{dt}\) is a statement of:
1. Ampere's law
2. Faraday's law of induction
3. Gauss' law of electricity
4. Gauss' law of magnetism
Subtopic: Â Maxwell's Equations |
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From NCERT
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Hints
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Match List-I with List-II (the symbols carry their usual meaning).
Choose the correct answer from the options given below:
| List-I | List-II | ||
| A. | \( \oint \vec{E} \cdot d \vec{A}=\dfrac{Q}{\varepsilon_0}\) | I. | Ampere-Maxwell's law |
| B. | \( \oint \vec{B} \cdot d \vec{A}=0 \) | II. | Faraday's law |
| C. | \( \oint \vec{E} \cdot d\vec{ l}=\dfrac{-d(\phi)}{d t} \) | III. | Gauss's law of electrostatics |
| D. | \( \oint \vec{B} \cdot d\vec{l}=\mu_0 i_c+ \mu_0 \varepsilon_0 \dfrac{d\left(\phi_E\right)}{d t}\) | IV. | Gauss's law of magnetism |
Choose the correct answer from the options given below:
| 1. | A-III, B-IV, C-II, D-I |
| 2. | A-IV, B-III, C-II, D-I |
| 3. | A-III, B-II, C-IV, D-I |
| 4. | A-IV, B-I, C-III, D-II |
Subtopic: Â Maxwell's Equations |
 85%
From NCERT
NEET - 2024
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