- 1(current)
Q. No.In a nuclear reaction, \(2~\text{amu}\) mass is converted into energy. Using Einstein's mass-energy relationship, the amount of energy released is:
1. \(1863~\text{J}\)
2. \(931.5~\text{MeV}\)
3. \(1863~\text{MeV}\)
4. \(931.5~\text{J}\)
1. \(1863~\text{J}\)
2. \(931.5~\text{MeV}\)
3. \(1863~\text{MeV}\)
4. \(931.5~\text{J}\)
Subtopic: Â Mass-Energy Equivalent |
 85%
From NCERT
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The energy required in \(\text{MeV/c}^2 \) to separate \({ }_8^{16} \mathrm{O}\) into its constituents is:
(Given: mass defect for \({ }_8^{16} \mathrm{O}=0.13691~ \text{amu}\))
| 1. | \(127.5\) | 2. | \(120.0\) |
| 3. | \(222.0\) | 4. | \(119.0\) |
Subtopic: Â Mass-Energy Equivalent |
 68%
From NCERT
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If \(M(A,~Z)\), \(M_p\), and \(M_n\) denote the masses of the nucleus \(^{A}_{Z}X,\) proton, and neutron respectively in units of \(u\) \((1~u=931.5~\text{MeV/c}^2)\) and represent its binding energy \((BE)\) in \(\text{MeV}\). Then:
| 1. | \(M(A, Z) = ZM_p + (A-Z)M_n- \dfrac{BE}{c^2}\) |
| 2. | \(M(A, Z) = ZM_p + (A-Z)M_n+ BE\) |
| 3. | \(M(A, Z) = ZM_p + (A-Z)M_n- BE\) |
| 4. | \(M(A, Z) = ZM_p + (A-Z)M_n+ \dfrac{BE}{c^2}\) |
Subtopic: Â Mass-Energy Equivalent |
 72%
From NCERT
AIPMT - 2008
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