Match the following:

List I List II
A. Adiabatic process i. At constant temperature
B. Isolated system ii. No transfer of heat
C. Isothermal change iii. Heat
D. Path function iv. No exchange of energy and matter

Codes:

A B C D
1. ii  iv  iii 
2. iii  iv  i ii
3. iv iii  i ii
4.  iv  ii i iii

Subtopic:  First Law of Thermodynamics | Classification of System, Extensive & Intensive Properties |
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Match the item in column I and in column II.
Column I
(Process)
Column II
(Expression)
a. No heat is absorbed by the system from the surroundings, but work (w) is done on the system. i. ∆U = q – w, closed system.
b. No work is done on the system, but q amount of heat is taken out from the system and given to the surroundings. ii. ∆U = wad, a wall is adiabatic.
c.  w amount of work is done by the system and q amount of heat is supplied to the system. iii. ∆U  = –q, thermally conducting walls.
 
1. a = i; b = ii; c = iii 2. a = ii; b = i; c = iii
3. a = ii; b = iii; c = i 4. a = iii; b = ii; c = i
Subtopic:  First Law of Thermodynamics |
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1 mol of monoatomic ideal gas expanded adiabatically against a constant pressure of 2 atm from 10L to 20L. The correct option for the above process is:

1. q = 20 L-atm 
2. \(\Delta U = 0 \)
3. \(\Delta U = -20 ~\text L~\text {atm} \)
4. \(\text w = 10 ~\text L~ \text {atm} \)
Subtopic:  First Law of Thermodynamics |
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An ideal gas is allowed to expand form 1 L to 10 L against a constant external pressure of 1 bar. The work done in kJ is:
1.  +10.0
2.  – 9.0
3.  – 2.0
4.  –0.9

Subtopic:  First Law of Thermodynamics |
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The work done when a kettle containing 1 kg of water is heated open to the atmosphere until evaporation is complete is:

1. 172.28 J 
2. 172.27 kJ
3. 126.09 kJ
4. 126.09 J
Subtopic:  First Law of Thermodynamics |
 58%
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The work done during the expansion of a gas from a volume of 4 dm3 to 6 dm3 against a constant external pressure of 3 atm is:

1. –608 J

2. +304 J

3. –304 J

4. –6 J 

Subtopic:  First Law of Thermodynamics |
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AIPMT - 2004
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An ideal gas expands isothermally from 10-3m3 to 10-2 m3 at 300 K against a constant pressure of 105 Nm-2. The work done by  the gas is:

1. +270 kJ 2. –900 J
3. +900 kJ 4. –900 kJ
Subtopic:  First Law of Thermodynamics |
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The pressure-volume work for an ideal gas can be calculated by using the expression W=ViVfpexdV.

The work can also be calculated from the pV-plot by using the area under the curve within the specified limits.
An ideal gas is compressed (a) reversibly or (b) irreversibly from volume Vi to Vf.
The correct option is:

1. W (reversible)=W (irreversible)

2. W (reversible)<W(irreversible)

3. W (reversible)>W (irreversible)

4. W (reversible)=W (irreversible)+pex.V

Subtopic:  First Law of Thermodynamics |
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3 moles of helium gas at 1 bar is compressed reversibly and isothermally at 400 K to 10 bar pressure. The work done (in J) on the system is: (Given: \(R= 8.314 ~J K^{-1}~ mol^{-1}\) )

1. \(2.29 \times 10^4 \)
2. \(2.29 \times 10^{-4} \)
3. \(-2.29 \times 10^4 \)
4. \(-2.29 \times 10^{-4} \)
Subtopic:  First Law of Thermodynamics |
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When the pressure on 10 g of hydrogen is reduced from 20 atm to 1 atm at a constant temperature of 273 K and the gas behaves ideally, then the value of q is: 
(Given: 1.30)
1. 9280 cal.
2. 8180 cal. 
3. -7960 cal.
4. -6570 cal.
Subtopic:  First Law of Thermodynamics |
 61%
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